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pashok25 [27]
3 years ago
5

2. How many moles of salt are present in 1.5L of a 5.OM salt water solution?

Chemistry
1 answer:
madam [21]3 years ago
8 0

Answer:

There are 7.5 moles of salt

Explanation:

5.0M means that in every liter of solution, there are 5 moles of salt. So, 1.5L of solution times 5 moles per liter equals 7.5 moles

You might be interested in
In which of the following compounds is the mass ratio of chromium to oxygen closest to 1.62 to 1.00?
ohaa [14]

Answer:

The answer to your question is letter A

Explanation:

Data

Mass ratio 1.62 to 1.00

Atomic mass Cr = 52 g

Atomic mass O  = 16

Process

1.- Calculate the proportion Chromium to Oxygen to each possible solutions

a) CrO₃   =   \frac{52}{16 x 3} = \frac{52}{48} = 1.08

b) CrO₂   =   \frac{52}{16 x 2} = \frac{52}{32} = 1.63

c) CrO     = \frac{52}{16} = 3.25

d) Cr₂O   =  \frac{52 x 2}{16} = \frac{104}{16} = 6.5  

8 0
3 years ago
Calculate the pressure (in kpa) of 1.5 mole of helium gas at 354 k when it occupies a volume of 16.5l.
3241004551 [841]

Answer:

267.57 kPa

Explanation:

Ideal gas law:

PV = n RT        R = 8.314462    L-kPa/K-mol

P (16.5) = 1.5 (8.314462)(354)       P = 267.57 kPa

8 0
2 years ago
How many liters of carbon dioxide will be produced when 89.5 L of ethane are burned? (One mole of any gas occupies 22.4 L under
yan [13]

Answer:

179 L of CO2

Explanation:

Given the equation of the reaction;

C2H6(g) + 7/2 O2(g) -------> 2CO2(g) + 3H2O(g)

Now 1 mole of ethane yields 2 moles of CO2 from the balanced reaction equation

1 mole of a gas occupies 22.4 L volume so,

22.4 L of ethane yields 44.8 L of CO2

89.5 L of ethane yields 89.5 * 44.8/22.4 = 179 L of CO2

4 0
3 years ago
2. (Exercise 4.1.6) A liquid adhesive consists of a polymer dissolved in a solvent. The amount of polymer in the solution is imp
Lilit [14]

Answer:

800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

Explanation:

3000 lb of 13% solution is required .

Total adhesive in weight = 3000 x .13 = 390 lb of adhesive

Available = 500 lb of 10% solution = 50 lb of adhesive

Rest = 390 - 50 = 340 lb required .

rest mass of solution = 3000 - 500 = 2500 lb

mass of adhesive required = 340 lb

Let the mass  of 20% required be V

mass of adhesive = .20 V

.20 V = 340

V = 1700

rest of the volume = 2500 - 1700 = 800 lb which will be of pure solvent

So 800 lb of pure solvent , 1700 lb of 20% solution and 500 lb of 10% solution will be mixed to form 3000 lb of 13 % solution .

6 0
4 years ago
What is the volume in liters of hydrogen gas that would be produced by the reaction of 40.0 g of Al with excess HCl at STP accor
DaniilM [7]

The volume in liters of Hydrogen gas = 49.28 L

<h3>Further explanation </h3>

The reaction equation is the chemical formula of reagents and product substances  

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products  

Reaction

2 Al (s) + 6 HCl (aq) → 2 AlCl₃ (aq) + 3 H₂ (g)

mol Al :

\tt mol=\dfrac{mass}{Ar}=\dfrac{40}{27}=1.481

mol  H₂ :

\tt \dfrac{3}{2}\times 1.481=2.2

At STP, 1 mol =22.4 L

so the volume of hydrogen :

\tt 2.2 \times 22.4=49.28~L

8 0
3 years ago
Read 2 more answers
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