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3 years ago

How to Measure the mass of a coin using a triple beam balance

Physics

1 answer:

Sphinxa [80]3 years ago

6 0

Answer:

https://youtu.be/stW-C7F7QOg

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___________ relates the quantities of pressure, volume, temperature, and quantitiy of moles.

Gnoma [55]

C.) The relationship between volume, temperature, pressure and quantity of moles is given by ideal gas law. Mathematically given by PV = nRT.

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3 years ago

What is a scavenger give some examples

STALIN [3.7K]

an animal that feeds on carrion, dead plant material, or refuse

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3 years ago

An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s . How fast wil

viktelen [127]

Answer:

The speed of the quarterback backward is $v_q = 0.08 \ m/s$

Known are

$m_Q , m_B , (v_{Bx})_i (v_{Qx})_f, (v_{Bx})_f$

Unknown

$(v_{Qx})_f$

Explanation:

From the question we are told that

The mass of the quarterback is $m_Q = 80 \ kg$

The mass of the ball is $m_B = 0.43 \ kg$

The speed of the ball is $v_{B x}= 15 \ m/s$

The law of momentum conservation can be mathematically represented as

$m_Q u_{Qx} + m_Bu_{Bx} = - m_{Q} v_{Qx} + m_B v_{Bx}$

Now at initial both ball and quarterback are at rest and the negative sign signify that the quarterback moved backwards after throwing the ball

$m_Q v_{Qx} = m_B v_ {Bx}$

=> $v_{Qx} = \frac{m_Bv_{Bx}}{m_Q}$

substituting values

$v_q = \frac{0.43 * 15}{80}$

$v_q = 0.08 \ m/s$

5 0

3 years ago

What is 1 + 1 - 1 + 2 - 1 - 1<br>This is just to get answers

geniusboy [140]

Answer:

answer is 1

Explanation:

4 0

3 years ago

Read 2 more answers

a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced

Alina [70]

Answer:

$\boxed{\sf Heat \ produced \ (H) = 5 \ kWh}$

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

$\boxed{ \bold{ \sf H = I^2Rt}}$

Substituting values of I, R & t in the equation:

$\sf \implies H = {5}^{2} \times 100 \times 2 \\ \\ \sf \implies H = 25 \times 100 \times 2 \\ \\ \sf \implies H = 5000 \\ \\ \sf \implies H = 5 \: kWh$

$\therefore$

Heat developed (H) in the electric iron = 15 kWh

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3 years ago