Answer:
The total Mechanical energy will be zero
Explanation: Escape velocity is the velocity required by a free object in order to overcome the impact of the force of gravity. The total mechanical energy of an object is the total energy possessed by an object which includes its kinectic and potential energy.
since the object is moving at an escape velocity which is 11.2m/s the object will be assumed to be weightless
Etotal = kinetic energy + potential energy
kinetic energy= 1/2*M*V*V
Potential energy=MGH
Etotal=1/2*0*11.2*11.2+0*0*0
Etotal=0+0
Etotal=0.
 
        
             
        
        
        
To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

Here,
 = Angle between areal vector and magnetic field direction.
 = Angle between areal vector and magnetic field direction. 
According to Faraday's law, induced emf in the loop is,





At time  ,  Induced emf is,
,  Induced emf is,


Therefore the magnitude of the induced emf is 10.9V
 
        
                    
             
        
        
        
Answer:
vB = 15.4 m/s 
Explanation:
Principle of conservation of energy:
Because there is no friction the mechanical energy is conserve
ΔE = 0
ΔE : mechanical energy change (J)
K : Kinetic energy (J)
U: Potential energy (J)
K = (1/2)mv²
U = m*g*h
Where :
m: mass (kg)
v : speed (m/s)
h : hight (m)
Ef - Ei = 0
(K+U)final - (K+U)initial =0
(K+U)final = (K+U)initial 
((1/2)mv²+m*g*h)final = ((1/2)mv²+m*g*h)initial , We divided by m both sides of the equation:
((1/2)vB² + g*hB = (1/2 )vA²+ g*hA
(1/2) (vB)² + (9.8)*(14.7) =  0 + (9.8)(26.8 ) 
(1/2) (vB)² = (9.8)(26.8 ) - (9.8)*(14.7)
 (vB)² = (2)(9.8)(26.8 - 14.7)
 (vB)² = 237.16 

vB = 15.4 m/s : speed of the cart at B