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Luden [163]
3 years ago
13

Which of the following materials has the highest density?

Chemistry
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer:

Answer is C. liquid water.

Explanation:

I hope it's helpful!

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An atom of hydrogen and an atom of carbon are
LenKa [72]

Answer: -

Organic compounds consisting of only carbon atoms and hydrogen atoms are known as hydrocarbons.

Hydrocarbons are used by us for mainly as a source of energy. Hydrocarbons make up gasoline which is used as fuel in automobiles.

Hydrocarbons depending on the type of unsaturation can be of three types - alkanes, alkenes and alkynes.

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4 years ago
Qué es la hidrólisis​
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Explanation:    es una reacción química entre una molécula de agua y otra macromolécula, en la cual la molécula de agua se divide y rompe uno o más enlaces químicos y sus átomos pasan a formar unión de otra especie química.

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3 years ago
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Which molecular compound could be dinitrogen monoxide?
kari74 [83]
It could be Nitrous oxide


3 0
3 years ago
If a 32.5 mL of a 15.1 M HCl solution was diluted to 3.25 L with water, what is the final concentration?
user100 [1]

Answer:

The final concentration is 0,151 M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We convert the unit of volume in L into ml: 3,25 x 1000= 3250 ml

We use the formula for dilutions:

C1 x V1 = C2 x V2

C2= (C1 xV1)/V2

C2= (32, 5 ml x 15, 1 M)/ 3250 ml

<em>C2=0,151 M</em>

8 0
4 years ago
How many grams of phosphorus are in 500.0 grams of calcium phosphide? (i need the work also)
kvv77 [185]

Answer:

\boxed{\text{170.0 g P}} 

Explanation:

The formula of calcium nitride is Ca₃P₂.

The masses of each element are:

\begin{array}{lrcr}\text{3Ca:} & 3 \times 40.08&=& \text{120.24 u}\\\text{2P:} & 2\times 30.97&=& \text{61.94 u}\\& \text{TOTAL} & = & \text{182.18 u}\\\end{array}

So, there are 61.94 g of P in 182.18 g of Ca₃P₂.

In 500 g of Ca₃P₂:

\text{Mass of P} = \text{500.0 g Ca$_{3}$P$_{2}$} \times \dfrac{\text{61.94 g P}}{\text{182.18 g Ca$_{3}$P$_{2}$}} = \text{170.0 g P}

There are \boxed{\textbf{170.0 g P}} in 500.0 g of Ca₃P₂.

3 0
3 years ago
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