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2 years ago

A sample of nitrogen occupies 10.0 liters at 25°C what would be the new volume at 20°C? 7.9 L Ob 9.8 L 10.2 L 10.6 L

Chemistry

1 answer:

PtichkaEL [24]2 years ago

7 0

Answer:

9.4 liter

Explanation:

1) Data:

V₁ = 10.0 L

T₁ = 25°C = 25 + 273.15 K = 298.15 K

P₁ = 98.7 Kpa

T₂ = 20°C = 20 + 273.15 K = 293.15 K

P₂ = 102.7 KPa

V₂ = ?

2) Formula:

Used combined law of gases:

PV / T = constant

P₁V₁ / T₁ = P₂V₂ / T₂

3) Solution:

Solve the equation for V₂:

V₂ = P₁V₁ T₂ / (P₂ T₁)

Substitute and compuite:

V₂ = P₁V₁ T₂ / (P₂ T₁)

V₂ = 98.7 KPa × 10.0 L × 293.15 K / (102.7 KPa × 298.15 K)

V₂ = 9.4 liter ← answer

You can learn more about gas law problems reading this other answer on

Explanation:

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Hydrogen gas at a pressure of 740. mmHg has a volume of 2.00 L at a temperature of 25.0°C. What is the temperature of this gas a

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Explanation:

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Formula:

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P₁V₁/T₁ = P₂V₂/T₂

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If the sample has a total mass of 5.76 g and contains 1.79 g k, what are the percentages of kbr and ki in the sample by mass

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Molar mass is defined as the mass contained in 1 mole of sample.

It is given that

the sample has a total mass of 5.76 g contains KBr and KI

and contains 1.79 gm of K is present

what is the percentage of KBr and KI in the sample

Molecular weight of K = 39

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Molecular weight of I = 126.9

In KBr the mass percentage of K is 39/(39+79.9) = 32.89%

In KI the mass percentage of K is 39/(39+126.9) = 23.5%

Let the mass of KBr present in the sample is x

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