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Hoochie [10]
3 years ago
15

1. Draw the free body diagram for a parked car

Physics
1 answer:
avanturin [10]3 years ago
7 0

Answer:

can't do it here

Explanation:

can't draw in here sorry dude

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A 50.0 kg piece of rock slides down the side of Mt. Etna. That part of the volcano slopes up at 30.0° (from the horizontal). If
vesna_86 [32]

Answer:

0.224

Explanation:

There are two forces acting on the rock along the direction parallel to the slope:

- The component of the weight parallel to the slope, down, given by

mg sin \theta

where

m = 50.0 kg is the mass of the rock

g=9.8 m/s^2 is the acceleration of gravity

\theta=30^{\circ} is the angle of the slope

- The force of friction, up along the slope, given by

F_f=\mu R

where

\mu is the coefficient of friction

R is the normal reaction

So the equation of the forces along the direction parallel to the slope is

mg sin \theta - \mu R = ma (1)

where

a=3.0 m/s^2 is the acceleration

The normal reaction R can be found by looking at the equation of the forces along the direction perpendicular to the slope: in fact, we have that R balances the component of the weight perpendicular to the slope, so

R=mg cos \theta

And substituting into (1)

mg sin \theta - \mu mg cos \theta = ma

And solving for \mu, we find the coefficient of friction:

\mu = \frac{g sin \theta -a}{g cos \theta}=\frac{(9.8)(sin 30)-3.0}{(9.8)(cos 30)}=0.224

7 0
4 years ago
A 2.0 mm diameter wire of length 20 m has a resistance of 0.25 ȍ. what is the resistivity of the wire?
olasank [31]
The relationship between resistance R and resistivity \rho is
R= \frac{\rho L}{A} (1)
where L is the length of the wire and A is the cross-sectional area.

In our problem, the radius of the wire is half the diameter: r=1 mm=0.001 m, so the cross-sectional area is
A=\pi r^2 = \pi (0.001 m)^2=3.14 \cdot 10^{-6} m^2
The length of the wire is L=20 m and the resistance is R=0.25 \Omega.

By re-arranging equation (1), we can find the resistivity of the wire:
\rho =  \frac{RA}{L}= \frac{(0.25 \Omega)(3.14 \cdot 10^{-6} m^2)}{(20 m)} = 3.93 \cdot 10^{-8} \Omega \cdot m
5 0
3 years ago
Which model could represent a neutral atom of oxygen?<br> A. 2<br> B. 4<br> C. 3<br> D. 1
Sergeu [11.5K]
Answer: D. 1

Explanation:

Choice 1 could represent a neutral atom of oxygen
4 0
3 years ago
Read 2 more answers
Cart 1 has an initial velocity and hits cart 2 which is stationary. after a perfectly inelastic collision, the combined carts ar
Tomtit [17]

Option(a)  the mass of cart 2 is twice that of the mass of cart 1 is the right answer.

The mass of cart 2 is twice that of the mass of cart 1  is correct about the mass of cart 2.

Let's demonstrate the issue using variables:

Let,

m1=mass of cart 1

m2=mass of cart 2

v1 = velocity of cart 1 before collision

v2 = velocity of cart 2 before collision

v' = velocity of the carts after collision

Using the conservation of momentum for perfectly inelastic collisions:

m1v1 + m2v2 = (m1 + m2)v'

v2 = 0 because it is stationary

v' = 1/3*v1

m1v1 = (m1+m2)(1/3)(v1)

m1 = 1/3*m1 + 1/3*m2

1/3*m2 = m1 - 1/3*m1

1/3*m2 = 2/3*m1

m2 = 2m1

From this we can conclude that the mass of cart 2 is twice that of the mass of cart 1.

To learn more about inelastic collision visit:

brainly.com/question/14521843

#SPJ4

4 0
2 years ago
If you are doing a "rowing" motion, what muscle of the shoulder are you using?
Andrej [43]
The upper back muscles being worked while using a rowing machine .your upper trapezius and rhomboids located between your shoulder blades, and latissimus dorsi located beneath the armpits
6 0
3 years ago
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