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3 years ago

What are two properties that lead to ElectroMagnetic Interactions? please help this is due very soon!!!

Physics

1 answer:

melisa1 [442]3 years ago

7 0

Answer:

Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.

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What is the kinetic energy of a 0.01 kg dart that is thrown at 20m/s

Gekata [30.6K]

Mass of the dart = 0.01 kg
Speed at which the dart is thrown = 20 m/s
Kinetic Energy = (1/2) * mass * speed * speed
= (1/2) * (0.01) * (20) * (20) Joules
= (400 *0.01)/2 Joules
= 4/2 Joules
= 2 Joules
So the kinetic energy of the dart is 2 Joules. I hope this is the correct answer and it has helped you.

3 0

3 years ago

The term 'balanced diet' best means a person is getting which of the following? O A fewer nutrients and vitamins than it needs.

Sidana [21]

Answer:

A Balanced diet is the receiving of the right amount of nutrients and vitamins that the body needs for proper functioning

3 0

3 years ago

Read 2 more answers

Mr.nguyen decides to walk to school. How long does it take him to walk 10000m if he is traveling with a constant velocity of 2m/

exis [7]

Answer:

5000 s

Explanation:

Mr. Nguyen is moving in uniform motion (constant speed), therefore the distance he covers is given by the equation:

$d=vt$

where

d is the distance

v is the speed

t is the time taken

Here we have

d = 10000 m

v = 2 m/s

Solving for t, we find the time taken to cover this distance:

$t=\frac{d}{v}=\frac{10000}{2}=5000 s$

8 0

4 years ago

When you drop a 4.5 kg watermelon off the Dennison building, it reaches a terminal velocity of around 35 m/s second before smash

mart [117]

Answer:

3) 52500N

Explanation:

We use the mathematical definition of impulse as follows;

$Ft = mv............(1)$

were F is the force experienced, t is the time of impact, m is the mass of the object and v is the velocity of impact.

Given; m = 4.5kg, v = 35m/s, t = 3 milliseconds

however, $3milliseconds=3*10^{-3}s$

From equation (1);

$F=\frac{mv}{t}.............(2)$ .

Substituting all necessary values into equation (2), we obtain the following;

$F=\frac{4.5*35}{3*10^{-3}}}\\\\F= \frac{157.5.5}{0.003}\\\\F=52500N$

6 0

3 years ago

At what height is an object that weighs 490 newtons if its gravitational potential energy is 4900 J?

Sergio [31]

Answer:

The height at which the object is moved is 10 meters.

Explanation:

Given that,

Force acting on the object, W = F = 490 N

The gravitational potential energy, P = 4900 J

We need to find the height at which the object is moved. We know that the gravitational potential energy is possessed due to its position. It is given by :

$P=mgh\\\\h=\dfrac{P}{mg}\\\\h=\dfrac{4900\ J}{490\ N}\\\\h=10\ m$

So, the height at which the object is moved is 10 meters. Hence, this is the required solution.

5 0

4 years ago