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lesya692 [45]
3 years ago
12

At what height is an object that weighs 490 newtons if its gravitational potential energy is 4900 J?

Physics
1 answer:
Sergio [31]3 years ago
5 0

Answer:

The height at which the object is moved is 10 meters.

Explanation:

Given that,

Force acting on the object, W = F = 490 N

The gravitational potential energy, P = 4900 J

We need to find the height at which the object is moved. We know that the gravitational potential energy is possessed due to its position. It is given by :

P=mgh\\\\h=\dfrac{P}{mg}\\\\h=\dfrac{4900\ J}{490\ N}\\\\h=10\ m

So, the height at which the object is moved is 10 meters. Hence, this is the required solution.

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ZanzabumX [31]
The magnitude of gravity is expressed in terms of its acceleration. So the magnitude of ' g ' at that altitude is exactly 6.5 m/s^2.
8 0
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A 0.095 kg tennis ball is traveling to the right at 40 m/s when it bounces of a wall and travels in the opposite direction it ca
Mashutka [201]

given that

mass of ball = 0.095 kg

initial velocity of ball towards the wall = 40 m/s

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now change in momentum is given as

\Delta P = m(v_f - v_i)

\Delta P = 0.095(30 - (-40))

\Delta P = 6.65 kg m/s

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3 years ago
Suppose that you are standing on a train accelerating at 0.20g. What minimum coefficient of static friction must exist between y
Ilia_Sergeevich [38]
Acceleration = (0.2 x g) = 1.96m/sec^2. 
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<span>Coefficient µ = 1.96/9.8 = 0.2 minimum. </span>

<span>Coefficient is a ratio, so holds true for any value of mass to find accelerating force acting. </span>
<span>e.g. 75kg = (75 x g) = 735N. </span>
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5 0
4 years ago
Read 2 more answers
A potential difference of 53 mV is developed across the ends of a 12.0-cm-longwire as it moves through a 0.27 T uniform magnetic
Klio2033 [76]

Answer:

The angle between the magnetic field and the wire’s velocity is 19.08 degrees.                                            

Explanation:

Given that,

Potential difference, V = 53 mV

Length of the wire, l = 12 cm = 0.12 m

Magnetic field, B = 0.27 T

Speed of the wire, v = 5 m/s

Due to its motion, an emf is induced in the wire. It is given by :

\epsilon=Blv\sin\theta

Here,

\theta is the angle between magnetic field and the wire’s velocity

\sin\theta=\dfrac{\epsilon}{Blv}\\\\\sin\theta=\dfrac{53\times 10^{-3}}{0.27\times 0.12\times 5}\\\\\sin\theta=0.327\\\\\theta=19.08^{\circ}

So, the angle between the magnetic field and the wire’s velocity is 19.08 degrees.

8 0
3 years ago
Help pls quick!!
Mazyrski [523]

Answer:

Answer is C

Explanation:

7 0
2 years ago
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