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3 years ago

At what height is an object that weighs 490 newtons if its gravitational potential energy is 4900 J?

Physics

1 answer:

Sergio [31]3 years ago

5 0

Answer:

The height at which the object is moved is 10 meters.

Explanation:

Given that,

Force acting on the object, W = F = 490 N

The gravitational potential energy, P = 4900 J

We need to find the height at which the object is moved. We know that the gravitational potential energy is possessed due to its position. It is given by :

$P=mgh\\\\h=\dfrac{P}{mg}\\\\h=\dfrac{4900\ J}{490\ N}\\\\h=10\ m$

So, the height at which the object is moved is 10 meters. Hence, this is the required solution.

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Blake and Sandra are having a rummage sale. Blake drags 3 boxes a distance of 10 meters each. He exerts a force of 20 newtons on

vampirchik [111]

For Blake:

3 boxes at a distance of 10 meters each, each box weighs 20 N

Work done by Blake = 3 * 10m * 20N
= 600 J
Power = 600 J/ 2 min
= 300 J/min

For Sandra:

4 boxes, 15 N each at a distance of 12 meters each.

Work done by Sandra = 4 * 15 N *12m
= 720 J
Power = 720 J/ 4 min
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Blake does less work than Sandra.
Blake's power is more than Sandra's.

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3 years ago

Read 2 more answers

A 15 N force and a 45 N force act on in object in opposite directions. What is the net force on the object?

vovikov84 [41]

Answer:

30N in the direction the 45N acts.

Explanation:

Fnet = F1 + F2 (the vector sum of the forces)

Assigning a positive direction to the 45N force and a negative direction to the 15N force gives:

Fnet = 45 - 15

Fnet = 30N

Since the answer is positive, it is in the direction the 45N force acts.

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3 years ago

A crane motor exerts 3,500.0 W to lift a load up 5 floors in 25.0 seconds. The crane did how much J of work.

sertanlavr [38]

Answer:

87,500 J

Explanation:

Power = energy / time

3,500.0 W = E / 25.0 s

E = 87,500 J

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3 years ago

When the ambulance passes the person (switching from moving towards him to moving away from him), the perceived frequency of the

dlinn [17]

To develop this problem we will apply the considerations made through the concept of Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. At first the source is moving towards the observer. Than the perceived frequency at first

$F_1 = F \frac{{343}}{(343-V)}$

Where F is the actual frequency and v is the velocity of the ambulance

Now the source is moving away from the observer.

$F_2 = F\frac{343}{(343+V)}$

We are also so told the perceived frequency decreases by 11.9%

$F_2 = F_1 - 9.27\% \text{ of } F_1$

$F_2 = F_1-0.0927F_1$

$F_2 = 0.9073F_1$

Equating,

$F\frac{343}{(343+V)}= 0.9073(F\frac{343}{(343-V)})$

$\frac{1}{(343+V)}= 0.9073\frac{1}{(343-V)}$

$0.9073(343+V) = 343-V$

$(0.9073)(343)+(0.9073)V = 343-V$

$V+0.9073V = 343-(0.9073)(343)$

Solving for V,

$V = 16.67 m/s$

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3 years ago

How can the sun have both a brightness of -26.73 and 4.83? Explain what these numbers mean.

Assoli18 [71]

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3 years ago