3 years ago

Is copper sulphate dissolving in water a chemical change or physical change and why?

1 answer:

8 0

Because copper sulphate is not an ionic substance, no bonds are changed when it is dissolved. Thus it has to be a physical change

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This is chemistry help

katovenus [111]

The first one is the correct answer

5 0

3 years ago

We can also use the equation for enthalpy change for physical phase changes. Consider the phase change H2O(l) → H2O(g). Calculat

VLD [36.1K]

Answer: The value of enthalpy of the given reaction is 44.000 kJ/mol , that is energy is supplied to water to change into water vapors

Explanation:

$H_2O(l)\rightarrow H_2O(g),\Delta H_{rxn}=?$

Enthalpy of formation of water in liquid state, $\Delta H_{f,H_2O(l)}=-285.820 kJ/mol$

Enthalpy of formation of water in gaseous state, $\Delta H_{f,H_2O(g)}=-241.820 kJ/mol$

$\Delta H_{rxn}=\sum \Delta H_f \text{of products}-\sum \Delta H_f \text{of reactants}$

$\Delta H_{rxn}=(-241.820 kJ/mol)-(-285.820 kJ/mol)=44.000 kJ/mol$

The value of enthalpy of the given reaction is 44.000 kJ/mol, that is energy is supplied to water to change into water vapors.

6 0

3 years ago

Read 2 more answers

______ contributes to the nitrogen cycle by removing nitrogen from the air and converting it into a form that is usable by plant

umka21 [38]

Answer: Bacteria✅

Explanation:

4 0

2 years ago

Iodine-138 decays by beta decay. What element does it produce?

iVinArrow [24]

${xe}^{138}$

Explanation:

the bottom number would be 54. This is because you add one to 53 to make it 54 and you add 0 to 138.

4 0

2 years ago

Read 2 more answers

Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo

Luda [366]

Answer:

0.800 mol of O2

Explanation:

<em>Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.</em>

The balanced equation for the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2

From the reaction;

6 mol of CO2 produces 6 mol of O2

0.0800 mol of CO2 would produce x mol of O2

6 = 6

0.0800 = x

Solving for x;

x = 6 * 0.800 / 6

x = 0.800 mol

5 0

2 years ago