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Veseljchak [2.6K]
3 years ago
6

15*\sqrt(72) (15 times root 72. I can't seem to enter a square root symbol)

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

Step-by-step explanation:ok so if you want too  do the the root symbl on what

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Help me answer this please
Leno4ka [110]

Answer:

y=38 °

Step-by-step explanation:

4 0
3 years ago
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Given: 5x + 3 &gt; 4x + 7.<br><br><br><br> Choose the graph of the solution set.
Natali5045456 [20]

Answer:

5x+3>4x+7

-4x      -4x

x+3>7

-3     -3

x>4

so the answer will be the second

Step-by-step explanation:

7 0
3 years ago
In a survey of first graders, their mean height was 51.6 inches with a standard deviation of 3.6 inches. Assuming the heights ar
ki77a [65]

Answer:

Step-by-step explanation:

In a survey of first graders, their mean height was 51.6 inches with a standard deviation of 3.6 inches. Assuming the heights are normally distributed, what height represents the first quartile of these students?

54.03 inches

48.57 inches

48.00 inches

49.17 inches

6 0
3 years ago
A triangle has one angle measuring 3x degrees. A second angle measures 2x + 20 degrees and the third angle measures 4x -20 degre
Maurinko [17]
All the interior angles of a triangle always add up to 180 degrees.

3x + (2x + 20) + (4x - 20) = 180
3x + 2x + 20 + 4x - 20 = 180
3x + 2x + 4x + 20 - 20 = 180
10x = 180
x = 180/10
Therefore, x = 18
4 0
4 years ago
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The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
4 years ago
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