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Veseljchak [2.6K]
3 years ago
6

15*\sqrt(72) (15 times root 72. I can't seem to enter a square root symbol)

Mathematics
1 answer:
Mazyrski [523]3 years ago
5 0

Answer:

Step-by-step explanation:ok so if you want too  do the the root symbl on what

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David's chocolate bar is 37% cocoa. If the weight of the chocolate bar is 51 grams, how many grams of cocoa does it contain? Rou
OverLord2011 [107]

Answer:

18.9

Step-by-step explanation:

You need to find 37% of 51

In other words: 37% x 51

3 0
3 years ago
(NO TROLLS 3 TIMES THE CHARM) In △ABC, AB = BC = 20 and DE ≈ 9.28. Approximate BD.
andreev551 [17]

Answer:

≈ 5.36

Step-by-step explanation:

If we have a triangle in which the angle measure of it being broken down are the same, that means that the legs in which the angle measures are the same will have the same length.

If we already know that DE ≈ 9.28, then we can subtract this from 20 and divide by two to get BD, which is equal to EC.

20-9.28=10.72\\10.72\div2=5.36

However, I'm not 100% sure about this answer.

Hope this helped (and I hope I'm right)

3 0
3 years ago
Read 2 more answers
Free points
marishachu [46]

Answer: IT EQUALS 2

Step-by-step explanation:

4 0
3 years ago
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Zoe is doing a survey to find the time her classmates spend playing video games. She asks the following question:
Vladimir [108]
The data she would collect would be grouping people depending on how much video games they played. 

This however, is not a statistical question. Instead, she should set for example: 1-3 hrs per week, 4-6 hrs, etc. People play different amounts of hours, and so you cannot set a specific number, it must be a "range-of-numbers".

Also the question itself is kinda judging and comparative

so overall, umm... this question isn't really good

hope this helps :D
7 0
4 years ago
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It has long been reported that human body temperature follows a normal distribution with a mean of 98.6 degrees Fahrenheit. Ther
Kay [80]

Solution :

The normal body temperature of any human body is considered to be 98.6$^\circ \ F$. But there is a constant debate about the body temperature of a long held standard to the body temperature.

It is given that :

Null hypothesis and alternate hypothesis :

$H_0 : \mu = 98.6$

And $H_A : \mu > 98.6$

n is given as = 180

Test statistics = 3.64

Prove = 0.018 < α = 0.05 (let reject null hypothesis for α = 0.05 )

Therefore, their results are statistically significant and the result is unlikely due to chance alone.

7 0
3 years ago
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