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Korvikt [17]
3 years ago
11

In the top row labeled Before Collision, the left train car approaches the right car with a grey arrow pointing to the left car

car. The left car has below it m subscript 1 = 600 kilograms v subscript 1 = 4 meters per second. The right car has below it m subscript 2 = 400 kilograms v subscript 2 = 0 meters per second. In the bottom row labeled After Collision, two train cars move away linked together with a grey arrow pointing toward the right of the car on the right.
Consider a system to be one train car moving toward another train car at rest. When the train cars collide, the two cars stick together.

What is the total momentum of the system after the collision?

800 kg • m/s
1,600 kg • m/s
2,400 kg • m/s
4,000 kg • m/s
Physics
2 answers:
padilas [110]3 years ago
8 0

Answer:

2,400 kg

Explanation:

evablogger [386]3 years ago
6 0
The answer is 2,400 kg • m/s
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When performing an.experiment similar to Millikan's oil drop, a student measured the following load magnitudes: 3.26x10 ^-19 C 5
torisob [31]

Answer:

Explanation:

We put the charges in the ascending order as follows

1.53 P

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where P is equal to 10⁻¹⁹

we round off given charges as follows

1.53 P → 1.6 P

3.26 P → 3.2 P

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We see that 2 nd to 4 th charges are integral multiples of first charge . That means these charges are supposed to be made of combination of first charge . So first charge appears to be minimum possible charge .

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3 years ago
Is cereal a soup? aCTUALLY EXPLAIN WHY OR WHY NOT!
choli [55]

Answer:

No

Explanation:

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8 0
3 years ago
A 0.41-kg particle has a speed of 5.0 m/s at point A and kinetic energy of 8.5 J at point B. (a) What is its kinetic energy at A
Kipish [7]

<u>Answer:</u>

A)The kinetic energy at a point A when a particle of .41 kg moves at a speed of 5.0 m/s is 5.125 J.

B)The speed at point B of the particle of .41 kg with Kinetic Energy 8.5 J is 6.44 m/s.

C)The total Work done by the particle is 3.375 J.

<u>A)Explanation </u>

From the given statements, we know  

Mass (m) = 0.41 kg

Velocity = 5.0 m/s

As we know Kinetic Energy (KE) = \frac{1}{2} \text { mass } \times \text { velocity }^{2}

Substituting the values in the above equation, we find

Kinetic Energy (KE) = \frac{1}{2} \text { mass } \times \text { velocity }^{2}

\frac{1}{2} \times 0.41 \times 5^{2}= 5.125 joule

(b) Explanation

From the given statements, we know  

Mass (m) = 0.41 kg

Kinetic Energy (KE) = 8.5 J

As we know Kinetic Energy (KE) = \frac{1}{2} \text { mass } \times \text { velocity }^{2}

Substituting the values in the above equation, we find

Kinetic Energy (KE) = \frac{1}{2} \times 0.41 \times \mathrm{v}^{2} = 8.5 J

Or, v^2 = \frac{8.5 \times 2}{0.41} = \frac{8.5 \times 2}{0.41}

Or, v = \sqrt{\frac{17}{0.41}}=6.439 m/s ~ 6.44 m/s

(c) Explanation

From the above given statements, we know  

Kinetic Energy at A = 5.125 J

Kinetic Energy at B = 8.5 J

As we know

Work Done = Change in Kinetic Energy (ΔKE)

So, Work Done (WD) = Kinetic Energy at B - Kinetic Energy at A

  WD = (8.5 – 5.125) J = 3.375 J

4 0
3 years ago
What is the opposition to the flow of AC produced by a magnetic field with generated back voltage (EMF) called?
jek_recluse [69]

Answer and Explanation :

The opposition of the flow of alternating current produced by a magnetic field is called inductive reactance it is denoted by X_L, The value of the inductive reactance depends on the value of inductance. The good thing about inductive reactance is that it is not responsible for the power loss as  resistance is responsible for the power loss  

5 0
4 years ago
Given the height of rod,length of shadow of tree and length of shadow of the rod, estimate the height of the tree? Given:height
diamong [38]

Answer:

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Explanation:

To obtain the estimated tree height :

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Substituting values into the formula :

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Using cross multiplication :

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Height of tree = (150 * 800) / 120

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Hence, estimate height of tree = 1000 cm

5 0
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