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kumpel [21]
3 years ago
12

Write a short note on convection of heatI will give brainlist ​

Physics
1 answer:
makvit [3.9K]3 years ago
7 0
Convection is the process of heat transfer in fluids by the actual motion of matter. It happens in liquids and gases. It may be natural or forced. It involves a bulk transfer of portions of the fluid.


Hope that helps
You might be interested in
!!!
slavikrds [6]

Answer:

0.5

Explanation:

I think it is this beacause if u have the answer you have that

5 0
2 years ago
Convert: Thermal conductivity value of 0.3 Btu/(h ft°F) to W/(m °C). Surface heat transfer coefficient value of 105 Btu/(h ft2 o
Finger [1]

Answer:

0.3 Btu/(h ft °F) = 0.5189 W/(m°C)

105 Btu/(h ft² °F) = 596.2215 W/(m²°C)

Explanation:

<u>Thermal conductivity of a substance is defined as the measure of the tendency of the substance to conduct heat.</u>

<u>The SI unit of thermal conductivity is W.m⁻¹K⁻¹ .</u>

From the question , 0.3 Btu/(h ft °F) is to be converted to W/(m°C)

Thus,

1 Btu/(h ft °F) = 1.7296 W/(m°C)

So,

0.3 Btu/(h ft °F) = 1.7296×0.3 W/(m°C) = 0.5189 W/(m°C)

Thus,

<u>0.3 Btu/(h ft °F) = 0.5189 W/(m°C)</u>

<u>Heat transfer coefficient is defined as proportionality constant between heat flux (Thermal power per unit area) and the temperature difference of the substance for that flow of heat.</u>

<u>The SI unit of thermal conductivity is W.m⁻²K⁻¹ .</u>

From the question , 105 Btu/(h ft² °F) is to be converted to W/(m²°C)

Thus,

1 Btu/(h ft² °F) = 5.6783 W/(m²°C)

So,

105 Btu/(h ft² °F) = 5.6783×105 W/(m²°C) = 596.2215 W/(m²°C)

Thus,

<u>105 Btu/(h ft² °F) = 596.2215 W/(m²°C)</u>

3 0
3 years ago
Which is the higher temperature? (Assume temperatures to be exact numbers.)(a)1.)265°C or 265°F?2.)265°C3.)265°F 4.)They are the
vazorg [7]

Remember the following formulas to convert temperatures between Farenheit and Celsius:

\begin{gathered} \text{ Farenheit to Celsius:} \\ C=\frac{5(F-32)}{9} \\  \\ \text{ Celsius to Farenheit:} \\ F=\frac{9}{5}C+32 \end{gathered}

Convert all the temperatures to Celsius to compare them.

<h2>Part a)</h2>

Convert 265ºF to Celsius:

\begin{gathered} C=\frac{5(F-32)}{9} \\  \\ =\frac{5(265-32)}{9} \\  \\ =129.444... \end{gathered}

Then, 265ºF is equal to 129.444...ºC. Then, 265ºC is higher than 265ºF.

The correct choice is option 2) 265ºC.

Part b)

Convert 370ºF to Celsius:

\begin{gathered} C=\frac{5(F-32)}{9} \\  \\ =\frac{5(370-32)}{9} \\  \\ =187.777...ºC \end{gathered}

Then, 370ºF is equal to 187.777...ºC. Then, 200ºC is higher than 370ºF.

The correct choice is option 2) 200ºC.

7 0
1 year ago
.. A 15.0-kg fish swimming at 1.10 m&gt;s suddenly gobbles up a 4.50-kg fish that is initially stationary. Ignore any drag effec
stira [4]

Answer:

(a) 0.846 m/s

(b) 2.097J

Explanation:

Parameters given:

Mass of big fish, M = 15 kg

Mass of small fish, m = 4.5 kg

Initial speed of big fish, U = 1.1 m/s

Initial speed of small fish, u = 0 m/s (it is stationary)

(a) We apply the principle of conservation of momentum:

Total initial momentum = Total final momentum

Since both fish have the same final speed, V, (the small fish is in the mouth of the big fish), we have:

MU + mu = (M + m)*V

(15 * 1.1) + (4.5 * 0) = ( 15 + 4.5) * V

16.5 = 19.5V

=> V = 16.5/19.5

V = 0.846 m/s

The speed of the large fish after the meal is 0.846 m/s.

(b) We need to find the change in Kinetic energy of the entire system to find the total mechanical energy dissipated.

Initial Kinetic energy:

KEini = (½ * M * U²) + (½ * m * u²)

KEini = (½ * 15 * 1.1²) + (½ * 4.5 * 0²)

KEini = 9.075 J

Final Kinetic Energy:

KEfin = (½ * M * V²) + (½ * m * V²)

KEfin = (½ * 15 * 0.846²) + (½ * 4.5 * 0.846²)

KEfin = 5.368 + 1.610 = 6.978 J

Change in kinetic energy will be:

KEfin - KEini = 9.075 - 6.978

ΔKE = 2.097 J

The energy dissipated in eating the meal is 2.097 J

5 0
3 years ago
What is the period of the kinetic or the potential energy change if the period of position change of an object attached to a spr
mylen [45]

Answer: 2.2 s

Explanation:

This is a simple harmonic motion problem. A simple Harmonic motion can be defined as special type of periodic oscillation where the restoring force is directly proportional to the displacement. The restoring force then acts in the direction opposite to the displacement.

All simple harmonic motion is sinusoidal.

PERIOD is the time required to complete a full cycle.

From the question, the period of position change of an object attached to a spring is 4.4 s. There are two potential energy and two kinetic energy maxima per period, therefore, we have 4.4/2 = 2.2 s.

3 0
3 years ago
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