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Dafna1 [17]
3 years ago
9

By what factor would your weight increase if you could stand on the sun? (never mind that you can't.)

Physics
1 answer:
Fofino [41]3 years ago
6 0

Gravity on the surface of sun is given as

g = \frac{GM}{R^2}

here we know that

M = 1.98 \times 10^{30} kg

R = 6.95 \times 10^8 m

now we will have

g = \frac{(6.67 \times 10^{-11})(1.98 \times 10^30)}{(6.95 \times 10^8)^2}

g = 273.4 m/s^2

now we need to find the ratio of weight on surface of sun and on surface of Earth

R = \frac{mg_{sun}}{mg_{earth}}

R = \frac{273.4}{9.8} = 28 times

so weight will increase by 28 times

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Answer:

F_g=461lb_f

Explanation:

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If r = d/2 = 645ft, then:

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In order to find force, use Newton's universal law of gravitation:

F_g=G\frac{m_1m_2}{d^2}

Where,

G= the gravitational constant:

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A rocket with total mass 3.00 3 105 kg leaves a launch pad at Cape Kennedy, moving vertically with an acceleration of 36.0 m/s2.
Simora [160]

Answer:

(b) 2.40 x 10^{3} kg/s

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Rate at which rocket was initially burning fuel = \frac{3.003*10^{5} }{125.0833}

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soldi70 [24.7K]

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