Answer:
the stove energy went into heating water is 837.2 kJ.
Explanation:
given,
mass of water = 2000 grams
initial temperature = 0° C
Final temperature = 100° C
specific heat of water (c) = 4.186 joule/gram
energy = m c Δ T
= 2000 × 4.186 × (100° - 0°)
= 837200 J
= 837.2 kJ
hence, the stove energy went into heating water is 837.2 kJ.
p=mv so wouldn't u multiply them?
Explanation:
Below is an attachment containing the solution.
8 tablespoons of water.
2 x 4 = 8
I hope this helps :)
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