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postnew [5]
3 years ago
12

The path the moon's umbra traces across earth's surface is the path of totality.What would you see if you were standing in the p

ath of totality?
Physics
1 answer:
ivann1987 [24]3 years ago
4 0
You would see the darkest part of the moon
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Two gliders are on a frictionless, level air track. Both gliders are free to move. Initially, glider A moves to the right and gl
Yuliya22 [10]

Answer:

The change in momentum of both objects is the same but in opposite direction.

Explanation:

Hi there!

The momentum of the system is calculated as the sum of the momentums of each glider. The momentum of the system is conserved if no external force is acting on the objects (as in this case). That means that the initial momentum of the system is equal to the final momentum of the system.

The momentum of each glider is calculated as follows:

p = m · v

Where:

p = momentum.

m = mass of the glider.

v = velocity.

The momentum of the system for glider A and B can be calculated as follows:

initial momentum = mA · vA + mB · vB

Where:

mA and vA = mass and velocity of glider A

mB and vB = mass and velocity of glider B

Initially, glider B is at rest so that vB = 0. Then, the initial momentum of the system is:

initial momentum = mA · vA

The final momentum of the system is calculated as follows:

final momentum = mA · vA´ + mB · vB´

Where vA´ and vB´ are the final velocities of glider A and B respectively.

We know that mB = 4mA and that vA´ is negative. The the final momentum will be:

final momentum = -mA · vA´ + 4mA · vB´

Since initial momentum = final momentum:

mA · vA = -mA · vA´ + 4mA · vB´

mA · vA + mA · vA´ = 4mA · vB´

<u>vA + vA´ = 4 vB´</u>

<u />

The change in momentum of glider A (ΔpA) is calculated as follows:

ΔpA = final momentum - initial momentum

ΔpA =  -mA · vA´ - mA · vA = -mA (vA + vA´) = -4mA · vB´

The change in momentum of glider B (ΔpB) is calculated as follows:

ΔpB = final momentum - initial momentum

ΔpB = 4mA · vB´ - 0 = 4mA · vB´

Then, the change in momentum of both objects is the same but in opposite direction. That´s why the momentum is conserved.

4 0
3 years ago
The distance from Earth to the star Epsilon Eridani is about 10.5 light years. Which of the following statements is true?
Simora [160]
<span>The correct answer is B. - It would take a ray of light 10.5 light years to travel from Earth to Epsilon Eridani, or vice-versa. Using our current technology it would take far longer than 21.0 years for a space ship from Earth to travel that far - I would have to guess many hundreds of years.</span>
4 0
4 years ago
Read 2 more answers
When a falling meteoroid is at a distance above the earth's surface of 2.60 times the earth's radius, what is its acceleration d
Mice21 [21]

The gravitational acceleration at any distance r is given by

g=  \frac{GM}{r^2}

where G is the gravitational constant, M the Earth's mass and r is the distance measured from the center of the Earth.

The Earth's radius is r_e=6.37 \cdot 10^6 m, so the meteoroid is located at a distance of:

r=r_e+2.60 r_e =3.60 r_e =  2.29 \cdot 10^7 m

And by substituting this value into the previous formula, we can find the value of g at that altitude:

g=  \frac{GM}{r^2} =  \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(2.29 \cdot 10^7 m)^2} =0.75 m/s^2

5 0
3 years ago
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What is the frequency of a wave that has a wavelength of 20 cm and a speed of 10 m/s
jarptica [38.1K]
You would probably have a low frequency due to how much the wavelength is spread out.
8 0
3 years ago
Consider a loop of wire with a resistor. In the same plane, (with switch S closed) a long wire has a current I flowing from left
Ulleksa [173]

Solution :

The given figure is a loop of a wire with a resistor.

When the switch S is closed for long time and is suddenly opened, the direction of the induced current can be find out by using the rule of right hand screw. According to the right hand screw rule, the direction of the magnetic field at the loop is in the direction that points outwards. The strength of the current rapidly decreases as it is switch off and the magnetic flux that is linked with the loop wire will also decrease.

According to the Lenz's law, the direction of the induced current must be such $\text{that it opposes}$ the decrease in the magnetic flux.  It means the direction of the magnetic field must be outwards and also normal to the plane of the screen. The direction of the induced anti clockwise or from right to left in the resistance.

6 0
3 years ago
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