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4 years ago

What happens when the temperature of an object decreases

Physics

1 answer:

Helen [10]4 years ago

5 0

The molecules become more stiff and move slowly

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A box of mass m1 rests on a smooth, horizontal floor next to a box of mass m2. Suppose the force of 20.0 N pushes on two boxes o

meriva

Answer:

Explanation:

Given

acceleration of system a =1.2 m/s^2

Normal Force N=4.45 N

Force exerted F=20 N

Thus

$F=(m_1+m_2)a$

$\frac{20}{1.2}=m_1+m_2$

$16.67=m_1+m_2$ -------1

Normal reaction $N=m_2a$

$4.45=m_2\times 1.2$

$m_2=3.70 kg$

therefore $m_1=16.67-3.70$

$m_1=12.96 kg$

8 0

3 years ago

Read 2 more answers

"The greater the height of an object, the *BLANK* its gravitational potential energy."

-Dominant- [34]

Answer:

the greater the height of an object the *greater* its gravitational potential energy

greater

3 0

2 years ago

Read 2 more answers

Please help me:(

Lelechka [254]

Answer:B

Explanation:

I’m doing the same thing you are!

3 0

3 years ago

A point charge of -0.70 μC is fixed to one corner of a square. An identical charge is fixed to the diagonally opposite corner. A

MakcuM [25]

Answer:

The magnitude and algebraic sign of q is $14\sqrt{2}\ \mu C$

Explanation:

Given that,

Point charge = -0.70 μC[/tex]

We need to calculate the force for all charges

The electric force at first corner

$F_{1}=\dfrac{-k0.70\times10^{-6}q}{r^2}$

The electric force at opposite corner

$F_{3}=\dfrac{-k0.70\times10^{-6}q}{r^2}$

The net force is

$F=\sqrt{F_{1}^2+F_{2}^2}$

Put the value into the formula

$F=\sqrt{(\dfrac{-k0.70\times10^{-6}q}{r^2})^2+(\dfrac{-k0.70\times10^{-6}q}{r^2})^2}$

The electric force at second corner

$F_{2}=\dfrac{-kq^2}{2r^2}$

The net force acting on either of the charges is zero.

So, $F=F'$

$\sqrt{(\dfrac{k0.70\times10^{-6}q}{r^2})^2+(\dfrac{-k0.70\times10^{-6}q}{r^2})^2}=\dfrac{kq^2}{2r^2}$

$\sqrt{2}\times\dfrac{0.70\times10^{-6}kq}{r^2}=\dfrac{kq^2}{2r^2}$

$q=14\sqrt{2}\ \mu C$

Hence, The magnitude and algebraic sign of q is $14\sqrt{2}\ \mu C$

8 0

3 years ago

Please any one help me

Hatshy [7]

Answer:

Which one are we supposed to do

Explanation:

4 0

3 years ago