The volume of the room is the product of its dimensions:
Now, from the equation
where d is the density, m is the mass and V is the volume, we deduce
So, multiply the density and the volume to get the mass of air in the room.
Answer:
See the answer below
Explanation:
<em>The best thing one can do in this case would be to return the microscope's objective to low power and then </em><em>re-center the specimen </em><em>before switching back to high-dry power.</em>
Most of the time, <u>what makes the specimen under the microscope to be out of focus at higher objective powers after being in focus at low power is because they are not properly centered on the stage</u>. Hence, before calling on the instructor, it would be wise to first return to low power, re-center the specimen and bring it into focus after which the high power objective can be returned to and the fine focus adjusted to bring the image back to focus.
After doing the above and the specimen still does not come into focus, then the instructor can be called upon.
Answer:
Explanation:
Moment of inertia of toy top = 3 x 10⁻² kgm²
Torque created = F x r
= .30 x 2.5 x 10⁻² N m
Torque = moment of inertia x angular acceleration
angular acceleration = .3 x 2.5 x 10⁻² / 3 x 10⁻²
α = .25 radian /s²
Angular displacement in 5 revolution θ = 5 x 2π = 10π radian
θ = ω₀t + 1/2 α t²
initial angular velocity ω₀ = 0
10π = 1/2 α t² = .5 x .25 t²
t² = 251.2
t = 15.85 s
Answer:
372,400 N
Explanation:
The volume of the column is ...
V = Bh = (2 m^2)(19 m) = 38 m^3
If we assume the density is 1000 kg/m^3, then the mass of the water is ...
M = ρV = (1000 kg/m^3)(38 m^3) = 38,000 kg
The force of gravity on that mass is ...
F = Mg = (38,000 kg)(9.8 m/s^2) = 372,400 N