Answer: a. How the mass of an extended object is distributed about a rotation axis
Explanation: Moment of inertia is defined as the measure of the rotational inertia of a solid object, it is a quantity that defines the torque needed to reach a desired angular acceleration around a given rotation axis, and it depends mainly on the mass distribution of the object, so the correct answer is: "how the mass of an extended object is distributed about a rotation axis"
Observations are used in order to collect data and record a variety of interesting or useful key points about the subject or specimen in observation. These observations, if made well, can be recorded and used to supplement a hypothesis.
The rod's mass moment of inertia is 5kgm².
<h3>Moment of Inertia:</h3>
The "sum of the product of mass" of each particle with the "square of its distance from the axis of rotation" is the formula for the moment of inertia.
The Parallel axis Theorem can be used to compute the moment of inertia about the end of the rod directly or to derive it from the center of mass expression. I = kg m². We can use the equation for I of a cylinder around its end if the thickness is not insignificant.
If we look at the rod we can assume that it is uniform. Therefore the linear density will remain constant and we have;
or = M / L = dm / dl
dm = (M / L) dl


Here the variable of the integration is the length (dl). The limits have changed from M to the required fraction of L.

![I = \frac{M}3L}[(\frac{L^3}{2^3} - \frac{-L^3}{2^3} )]\\\\I = \frac{1}{12}ML^2](https://tex.z-dn.net/?f=I%20%3D%20%5Cfrac%7BM%7D3L%7D%5B%28%5Cfrac%7BL%5E3%7D%7B2%5E3%7D%20%20%20-%20%5Cfrac%7B-L%5E3%7D%7B2%5E3%7D%20%29%5D%5C%5C%5C%5CI%20%3D%20%5Cfrac%7B1%7D%7B12%7DML%5E2)
Mass of the rod = 15 kg
Length of the rod = 2.0 m
Moment of Inertia, I = 
= 5 kgm²
Therefore, the moment of inertia is 5kgm².
Learn more about moment of inertia here:
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Answer:
925.04 J/s
Explanation:
T = 80 C = 80 + 273 = 353 K
To = 20 c = 20 + 273 = 293 K
A = 2 m^2
Use the formula for Stefan's law
Energy radiated per second


E = 925.04 J/s