Answer:
857.2947
Explanation:
You start with what you’re given 82g of H20 and multiply by 1 mole and the actual grams of h20 which is 18.0 then you do the mole. 1 mol of O2 and 2 mol of H2O times 6.02 x 10^23
Answer:
Q = -811440 J
Explanation:
Given data:
Mass of oil = 2.76 Kg (2.76× 1000 = 2760 g)
Initial temperature = 191 °C
Final temperature = 23°C
Specific heat capacity of oil = 1.75 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 23°C - 191 °C
ΔT = -168°C
Q = 2760 g ×1.75 J/g.°C ×-168°C
Q = -811440 J
Negative sign show heat is released.
Hey there!
mass of sample = 2.51 g of Aspirin
Number of moles of base ( NaOH ) :
M*V = 27.36*0.5106 = 13.9700 mmol of base
M*V = 13.68*0.516 = 7.05888 mmol of acid
pKa calculation:
pH = pKa + log(A-/HA)
3.48 = pKa + log(7.05888 / (13.9700 -7.05888))
Pka =3.49 - log(7.05888 / (13.9700 -7.05888))
pKa = 3.48
Molar mass calculation:
molar mass = mass/mol
(2.51)/(13.9700 *10⁻³) =
molar mass 180 g/mol approx
Hope that helps!
