Answer:
301.8 g
Explanation:
We prepare a solution with 200.4 g of water (solvent) and 101.42 g of salt (solute). The mass of the solution is equal to the sum of the mass of the solvent and the mass of the solute.
m(solution) = m(solute) + m(solvent)
m(solution) = 200.4 g + 101.42 g
m(solution) = 301.8 g (we round-off to one decimal according to the significant figures rules)
Answer:
1 mole of C2H6.
Explanation:
The balanced equation for the reaction is given below:
2C2H6 + 7O2 —> 4CO2 + 6H2O
We can determine the number of mole of C2H6 that reacted to produce 2 moles of CO2 as follow:
From the balanced equation above,
2 moles of C2H6 reacted to produce 4 moles of CO2.
Therefore, Xmol of C2H6 will react to produce 2 moles of CO2 i.e
Xmol of CO2 = (2 x 2)/4
Xmol of CO2 = 1 mole.
Therefore, 1 mole of C2H6 is required to produce 2 moles of CO2.
Answer:
28.497 cm3
Explanation:
Formula
D=m/v
Given data:
density = 19.3g/cm3
mass = 550 g
Now we will put the values in formula:
V=m/d
V=550 g/ 19.3 g/cm3 = 28.497 cm3
So the volume of gold is 28.497 cm3.
Answer:
The minimum volume of the container is 0.0649 cubic meters, which is the same as 64.9 liters.
Explanation:
Assume that ethane behaves as an ideal gas under these conditions.
By the ideal gas law,
,
.
where
is the pressure of the gas,
is the volume of the gas,
is the number of moles of particles in this gas,
is the ideal gas constant, and
is the absolute temperature of the gas (in degrees Kelvins.)
The numerical value of will be 
if , , and are in SI units. Convert these values to SI units:
;- shall be in cubic meters,
; 
.
Apply the ideal gas law:
.
