All categories

3 years ago

A 14 kg block lifted 5 m has a gravitational potential energy of

Physics

1 answer:

harina [27]3 years ago

8 0

Answer:

700 joules

Explanation:

potential energy = m × h × g

( m = mass, h = height, g = acceleration due to gravity )

P.E = 14 × 5 × 10
P.E = 700 J

hence, gravitational potential energy of the object is 700J

i hope it helped.....

You might be interested in

A. Blue light has higher energy than red light. Write 3 - 4 sentences comparing these electromagnetic waves with respect to the

frosja888 [35]

PART A)

As we know that energy of light depends on its wavelength and frequency as following formula

$E = \frac{hc}{\lambda} = h\nu$

now we know that wavelength of blue light is less than the red light so here energy of blue light will be more

also we know that

$\nu = \frac{c}{\lambda}$

so here if wavelength is smaller for blue light so its frequency will be high and the speed of both light will be same in same medium

PART B)

Since we know that frequency of blue light is more than red light as well as wavelength of blue light is less than the wavelength of blue light so here blue light will have more energy

When blue light and red light strike the metal surface then due to more energy of blue light it will release some loosely bonded electrons from metal surface which will contribute in current.

here if we increase the intensity of light then the number of photons that contain the blue light of certain energy will be more and that will contribute more current

So here quantification help as we know that due to quantization only certain frequency or energy will lead to eject electron so all colours will not give this current

5 0

3 years ago

Read 2 more answers

A cylindrical tank has a radius of 53 cm and a height of 1200 mm. It weighs 9.6 kN

xxTIMURxx [149]

Answer:

1985kg

Explanation:

assuming that

pi =3.14

oil density = 950kg/ cubic meter

g= 9.8m/s

$M=\frac{9600}{9.8 } + 950 * 3.14*.53^{2} *1.2=1985kg$

4 0

3 years ago

Calculate the location xcm of the center of mass of the Earth-Moon system. Use a coordinate system in which the center of the Ea

Jet001 [13]

Answer:

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

Explanation:

Let suppose that planet and satellite can be treated as particles. The masses of Earth and Moon ( $m_{E}$ , $m_{M}$ ) are $5.972\times 10^{24}\,kg$ and $7.349\times 10^{22}\,kg$ , respectively. The distance between centers is 384,403 kilometers. The location of the center of mass can be found by using weighted averages:

$\bar x = \frac{x_{E}\cdot m_{E}+x_{M}\cdot m_{M}}{m_{E}+m_{M}}$

If $x_{E} = 0\,km$ and $x_{M} = 384,403\,km$ , then:

$\bar x = \frac{(0\,km)\cdot (5.972\times 10^{24}\,kg)+(384,403\,km)\cdot (7.349\times 10^{22}\,kg)}{5.972\times 10^{24}\,kg+7.349\times 10^{22}\,kg}$

$\bar x = 4.673\,km$

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

8 0

3 years ago

A support crossbeam on a high speed train is made from a titanium rod that has a length of 0.650m when measured by an observer o

Vilka [71]

Answer:

A) The crossbeam is moving relative to the observer on the platform so the height appears contracted.

Explanation:

The observer on the train and the beam are in the same reference frame. That means observer on the train will measure the proper length of the beam not the contracted length . the observer is outside and the plank is in the moving system,it will appear to be moving.

3 0

4 years ago

1.)A tank travels at a rate of 10.0 km/hr for 12.00 minutes, then at 15.0 km/hr for 8.00

rosijanka [135]

12.00 min = 0.2 hr

8.00 min = 0.15 hr

Total distance:

(10.0 km/hr) (0.2 hr) + (15.0 km/hr) (0.15 hr) + (20.0 km/hr) (0.2 hr)

= 8.25 km

Average speed:

(10.0 km/hr + 15.0 km/hr + 20.0 km/hr) / 3

= 15 km/hr

Change in position:

(10.0 km/hr) (0.2 hr) + (15.0 km/hr) (0.15 hr) - (20.0 km/hr) (0.2 hr)

= 0.25 km

Average velocity:

(10.0 km/hr + 15.0 km/hr - 20.0 km/hr) / 3

≈ 1.67 m/s

8 0

3 years ago