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Alla [95]
3 years ago
10

A 2kg mass moving at a speed of 3 m/s is stopped by a constant force of 15N. How many seconds must the force act on the mass to

stop it.
Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

t = 0.4 seconds

Explanation:

Given that,

Mass of the object, m = 2 kg

Initial speed of the object, u = 3 m/s

Finally, it stops, v = 0

Constant force applied to the object, F = 15 N

We know that,

Force, F = ma

F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{2\times (0-3)}{15}\\\\=0.4\ s

So, it will take 0.4 seconds to stop the mass.

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A 20 kg mass is moving at 10 m/s and collides with a stationary 5 kg mass, transferring all its momentum in the collision, what
Fudgin [204]

Answer:

v = 40 [m/s].

Explanation:

Linear momentum is defined as the product of mass by Velocity. In this way, by means of the following equation, we can calculate the momentum.

P=m*v\\

where:

m = mass [kg]

v = velocity [m/s]

P =20*10\\P =200 [kg*m/s]

Since all momentum is transferred, we can say that this momentum is equal for the mass of 5 [kg]. In this way, we can determine the speed after the impact.

v = P/m\\v = 200/5\\v = 40 [m/s]

3 0
3 years ago
a cart has 30J or potential energy at the top of a 20m high hill. Assuming no energy is transformed to another form of energy, h
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Answer:

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Explanation:

3 0
3 years ago
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Andre45 [30]
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6 0
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The brachialis attaches to the forearm .035 m from the elbow at an angle of 32 deg. If the brachialis produces 750 N of force, w
jek_recluse [69]

Answer:

XY=636N

Explanation:

From the question we are told that:

Distance d=0.35m

Angle \theta=32\textdegree

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Generally the equation for magnitude of the stabilizing component of the brachialis force is mathematically given by

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Dennis_Churaev [7]
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