Answer:
= 7.07 m
Explanation:
The Tarzan reaches bottom of swing after descending 2.5 m,
change in his potential energy equals his kinetic energy at bottom of swing
m g h = (1/2) m v² ,
hence speed v of Tarzan at bottom of swing is given as
v = ( 2 g h )1/2
= ( 2 × 9.8 × 2.5 )1/2
= 7 m/s
At the bottom of swing, if the vine breaks, then he is moving with horizontal velocity 7 m/s in gravitational field.
If vertical distance from ground to bottom of swing is 5 m, then time t for Tarzan to reach ground is given by
S = (1/2)g t2 or t = (2S/g)1/2
= ( 2 × 5 / 9.8 )1/2
= 1.01 s
Horizontal distance traveled by Tarzan = 1.01 × 7
= 7.07 m
True.........................................
Answer: 116.926 km/h
Explanation:
To solve this we need to analise the relation between the car and the Raindrops. The cars moves on the horizontal plane with a constant velocity.
Car's Velocity (Vc) = 38 km/h
The rain is falling perpedincular to the horizontal on the Y-axis. We dont know the velocity.
However, the rain's traces on the side windows makes an angle of 72.0° degrees. ∅ = 72°
There is a relation between this angle and the two velocities. If the car was on rest, we will see that the angle is equal to 90° because the rain is falling perpendicular. In the other end, a static object next to a moving car shows a horizontal trace, so we can use a trigonometric relation on this case.
The following equation can be use to relate the angle and the two vectors.
Tangent (∅) = Opposite (o) / adjacent (a)
Where the Opposite will be the Rain's Vector that define its velocity and the adjacent will be the Car's Velocity Vector.
Tan(72°) = Rain's Velocity / Car's Velocity
We can searching for the Rain's Velocity
Tan(72°) * Vc = Rain's Velocity
Rain's Velocity = 116.926 km/h
