Answer:
A
Explanation:
True igneous rock forms cooling of magma fast on the top
Answer:
The final volume of the cylinder is 1.67 L
Explanation:
Step 1: Data given
Initial volume = 0.250 L
external pressure = 2.00 atm
Expansion does 288 J of work on the surroundings
Step 2: Definition of reversible work:
Wrev = -P(V2-V1) = -288 J
The gas did work, so V2>V1 (volume expands) and the work has a negative sign.(Wrev<0)
V2 = (-Wrev/P) + V1
⇒ with Wrev = reverse work (in J)
⇒ with P = the external pressure (in atm)
⇒ with V1 = the initial volume
We can see that your pressure is in atm and energy in J
To convert from J to L * atm we should use a convenient conversion unit using the universal gas constants :
R
=
8.314472 J/mol
*K and R= 0.08206 L*atm/K*mol
V2 =- (-288 J * (0.08206 L*atm/K*mol /8.314 J/mol
*K))/2.00 atm + 0.250L
V2 = 1.67 L
The final volume of the cylinder is 1.67 L
Probably when u close your eyes you’d see black or whenever you about to past out
Answer:
The enthalpy of the solution is -35.9 kJ/mol
Explanation:
<u>Step 1:</u> Data given
Mass of lithiumchloride = 3.00 grams
Volume of water = 100 mL
Change in temperature = 6.09 °C
<u>Step 2:</u> Calculate mass of water
Mass of water = 1g/mL * 100 mL = 100 grams
<u>Step 3:</u> Calculate heat
q = m*c*ΔT
with m = the mass of water = 100 grams
with c = the heat capacity = 4.184 J/g°C
with ΔT = the chgange in temperature = 6.09 °C
q = 100 grams * 4.184 J/g°C * 6.09 °C
q =2548.1 J
<u>Step 4:</u> Calculate moles lithiumchloride
Moles LiCl = mass LiCl / Molar mass LiCl
Moles LiCl = 3 grams / 42.394 g/mol
Moles LiCl = 0.071 moles
<u>Step 5:</u> Calculate enthalpy of solution
ΔH = 2548.1 J /0.071 moles
ΔH = 35888.7 J/mol = 35.9 kJ/mol (negative because it's exothermic)
The enthalpy of the solution is -35.9 kJ/mol