In addition to those in Table 14.3, other less stable nitrogen oxides exist. Draw a Lewis structure for each of the following:(c
1 answer:
Lewis structure for each of the following N₂O₃ with no N¬N bond is attached below.
Even though pi symmetry occupies the antibonding orbitals of NO, this is unimportant after the dimer forms. A sigma connection exists. The enthalpy of the newly formed sigma bond in the dimer is low because the loss of a particularly distinctive set of single-electron resonance forms that were available for no monomer offset the net gain in bond. When the whole free energy is taken into account, there is no gain because the entropic effects are on the order of 1030kJ/mol, and dimerization is entropically disfavored at G=17kJ/mol. Therefore, any little increase in enthalpy is cancelled out by the loss of entropy.
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Answer:
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Answer:
a. 10.0 g
Explanation:
The molar mass of NaOH is 39.997 grams which was calculated by adding the molar mass of Sodium, Oxygen, and Hydrogen . But before we do anything with this number we must first convert
molecules to moles. We can do this by dividing by Avogadro's number or
(
moles). We then convert moles to grams by multiplying by the molar mass of NaOH, (
grams). This is almost exactly 10 and the margin of error is likely due to the original numbers not being precise enough.