Unlike Electromagnetic waves, Mechanical waves need a to transfer energy

A 3.75 kg ball is lifted from the floor to a height of 1.5 m above the floor. What is its increase in potential energy?

inysia [295]

We can use a simple equation to calculate the increase in gravitational potential energy. PE = mgh m is the mass of the object g is the acceleration due to gravity h is the change in height PE = mgh PE = (3.75 kg) (9.80 m/s^2) (1.5 m) PE = 55.1 Joules The increase in gravitational potential energy is 55.1 Joules.

4 0

3 years ago

What is the energy equivalent of an object with a mass of 1. 05 g? 3. 15 Ă— 105 J 3. 15 Ă— 108 J 9. 45 Ă— 1013 J 9. 45 Ă— 1016 J

Molodets [167]

Considering the equivalence between mass and energy given by the expression of Einstein's theory of relativity, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

The equivalence between mass and energy is given by the expression of Einstein's theory of relativity, where the energy of a body at rest (E) is equal to its mass (m) multiplied by the speed of light (c) squared:

E=m×c²

This indicates that an increase or decrease in energy in a system correspondingly increases or decreases its mass, and an increase or decrease in mass corresponds to an increase or decrease in energy.

In other words, a change in the amount of energy E, of an object is directly proportional to a change in its mass m.

In this case, you know:

m=1.05 kg
c= 3×10⁸ m/s

Replacing:

E= 1.05 kg× (3×10⁸ m/s)²

Solving:

E= 9.45×10¹⁶ J

Finally, the correct answer is the last option: the energy equivalent of an object with a mass of 1.05 kg is 9.45×10¹⁶ J.

Learn more:

brainly.com/question/9477556

5 0

3 years ago

AuniformsphericalshellofmassM=4.5kgandradiusR=8.5cmcan rotate about a fixed vertical axis on frictionless bearings. A massless,

Kazeer [188]

Answer:

$v=1.42\frac{m}{s}$

Explanation:

There is no friction in the physical system. Thus, according to the law of conservation of energy, recall that the object is released from rest:

$\Delta E=0\\U=K_R+K_T\\mgh=\frac{I_p\omega_p^2}{2}+\frac{I_s\omega_s^2}{2}+\frac{mv^2}{2}$

Recall that the moment of inertia of a sphere is $I_s=\frac{2MR^2}{3}$ . The angular speed of the pulley is $\omega_p=\frac{v}{r}$ and the angular speed of the sphere is $\omega_s=\frac{v}{R}$ . So, we replace:

$mgh=\frac{I_pv^2}{2r^2}+\frac{2MR^2}{3}\frac{v^2}{2R^2}+\frac{mv^2}{2}\\mgh=v^2(\frac{I_p}{2r^2}+\frac{M}{3}+\frac{m}{2})\\v^2=\frac{mgh}{\frac{I_p}{2r^2}+\frac{M}{3}+\frac{m}{2}}\\\\v=\sqrt{\frac{(0.6kg)(9.8\frac{m}{s^2})(0.82m)}{\frac{3*10^{-3}kg\cdot m^2}{2(0.05m)^2}+\frac{4.5kg}{3}+\frac{0.6kg}{2}}}\\v=1.42\frac{m}{s}$

5 0

4 years ago

The slight negative charge at one end of one water molecule is attracted to the slight positive charge of another water molecule

aleksley [76]

Electromagnetic force. It is where alike forces ( negative, negative & positive , positive) repel and opposite forces ( negative & positive ) attract.
Hopes this helped

7 0

3 years ago

During normal beating, the heart creates a maximum 4.00-mV potential across 0.300 m of a person’s chest, creating a 1.00-Hz elec

erik [133]

Answer:

(a). The maximum electric field strength is 0.0133 V/m.

(b). The maximum magnetic field strength in the electromagnetic wave is $4.433\times10^{-11}\ T$