Question

A cylinder containing 14.71 L of helium gas at a pressure of 169.1 atm is to be used to fill toy balloons to a pressure of 1.086 atm. Each inflated balloon has a volume of 2.414 L. What is the maximum number of balloons that can be inflated? Report your answer to 1 decimal place. (Remember that 14.71 L of helium at 1.086 atm will remain in the exhausted (empty) cylinder)

Answer 1

Answer:

The number of balloons is 948.8.

Explanation:

The number of balloons can be calculated as follows:

$N = \frac{V_{f}}{V_{T}}$

Where:

$V_{f}$: is the volume at 1.086 atm

$V_{T}$: is the balloon volume = 2.414 L  

The volume at 1.086 atm can be found using Boyle's law:

$P_{i}V_{i} = P_{f}V_{f}$

$V_{f} = \frac{P_{i}V_{i}}{P_{f}} = \frac{169.1 atm*14.71 L}{1.086 atm} = 2290.5 L$

Now, the number of balloons is:

$N = \frac{V_{f}}{V_{T}} = \frac{2290.5 L}{2.414 L} = 948.8$

Therefore, the number of balloons is 948.8.

I hope it helps you!