Answer:
a) ω = 9.86 rad/s
b) ac = 194. 4 m/s²
c) minimum coefficient of static friction, µs = 19.8
Explanation:
a) angular speed, ω = 2πf, where f is frequency of revolution
1 rps = 6.283 rad/s, π = 3.142
ω = 2 * 3.14 * 0.25 * 6.28
ω = 9.86 rad/s
b) centripetal acceleration, a = rω²
where r is radius in meters; r = 200 cm or 2 m
a = 2 * 9.86²
a = 194. 4 m/s²
c) µs = frictional force/ normal force
frictional force = centripetal force = ma; where a is centripetal acceleration
normal force = mg; where g = 9.8 m/s²
µs = ma/mg = a/g
µs = 194.4 ms⁻²/9.8 ms⁻²
c) minimum coefficient of static friction, µs = 19.8
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
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Answer air circulating in a hot air balloon
Explanation:
Can I see the graph so I can help you
Answer:
![F'=2F](https://tex.z-dn.net/?f=F%27%3D2F)
Explanation:
The Coulomb's law states that the magnitude of the electrostatic force between two charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them:
![F=\frac{kq_1q_2}{d^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_1q_2%7D%7Bd%5E2%7D)
In this case, we have
:
![F'=\frac{kq'_1q_2}{d^2}\\F'=\frac{k(2q_1)q_2}{d^2}\\F'=2\frac{kq_1q_2}{d^2}\\F'=2F](https://tex.z-dn.net/?f=F%27%3D%5Cfrac%7Bkq%27_1q_2%7D%7Bd%5E2%7D%5C%5CF%27%3D%5Cfrac%7Bk%282q_1%29q_2%7D%7Bd%5E2%7D%5C%5CF%27%3D2%5Cfrac%7Bkq_1q_2%7D%7Bd%5E2%7D%5C%5CF%27%3D2F)