Answer:
Explanation:
let the velocity of throw is u .
Time to reach horizontally .25 m is equal to reach .45 m vertically
t = .25 / u cos63
= .55 / u
For vertical motion
- h = - ut + 1/2 gt²
-.45 = -usin63 x .55 / u + .5 x9.8 (.55 / u )²
-.45 = - .49 + 1.48 / u²
.04 = 1.48 / u²
u² = 37
u = 6.08 m /s
Water displacement. You fill a graduated cylinder with an amount of water, place the object inside the graduated cylinder, and then measure the new water level. The change in volume of the water is the volume of the object, assuming the object was completely submerged.
Samburu's weight is (mass x gravity) = (1650kg x 9.8 m/s²) = 16,170 Newtons.
Samburu's contact area with the ground is (0.25 m²/hoof) x (4 hoofs) = 1 m² .
Pressure = (force) / (area) = (16,170 Newtons) / (1 m²) = 16,170 Pascal .
Use pythagorean theorem and inverse tangent.
a) magnitude - 29.15; angle - 59 degrees
b) magnitude - 234.09; angle - 110 degrees
c) magnitude - 0.4; angle - south
d) magnitude - 234.3; angle - 309.81 degrees
e) magnitude - 42.43; angle - 315 degrees