2 years ago

Add 20 and 12, then, raise the sum to the 2nd power.

Mathematics

1 answer:

zubka84 [21]2 years ago

4 0

The answer to the question they gave you is D

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2 years ago

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√x+4=√3x A.) x=2 B.) x=-2 C.) x=3 D.) x=-3

Agata [3.3K]

I hope this helps you

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2 years ago

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If ( f ∘ g)(x) = x2 - 6x + 8 and g(x) = x - 3, what is f(x)?

DochEvi [55]

$\bf \begin{cases}
(f\circ g)(x)=x^2-6x+8\\\\
(f\circ g)(x)=f(~~g(x)~~)\\\\
g(x)=x-3\\
\end{cases}
\\\\\\
\textit{now, one probability is }x^2-1
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f(x)=x^2-1\implies f(~~g(x)~~)=(x-3)^2-1
\\\\\\
f(~~g(x)~~)=(x^2-6x+9)-1\implies f(~~g(x)~~)=x^2-6x+8$

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2 years ago

(n · 0.1) ÷ 3 = 0.1 What's N?

Ber [7]

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3 years ago

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Calculate the variance for the data set. Round your answer to the nearest hundredth. Show all of your steps. { 10 , 19 , 21 , 28

GrogVix [38]

Answer:

Variance of the given data = 31.143

Explanation:

Variance, $\sigma^2=\frac{1}{n} \sum_{i=1}^{n}(x_i-\mu)^2$ , where n is the number of observations, μ is the mean and $x_i$ is the observations made.

Number of observations, n = 7

Mean, μ = $\frac{10+19+21+28+12+20+16}{7} = 18$

$\sum_{i=1}^{n}(x_i-\mu)^2=(10-18)^2+(19-18)^2+(21-18)^2+(28-18)^2+(12-18)^2+(20-18)^2+(16-18)^2\\ \\ \sum_{i=1}^{n}(x_i-\mu)^2=64+1+9+100+36+4+4=218$

$\sigma^2=\frac{1}{n} \sum_{i=1}^{n}(x_i-\mu)^2=\frac{218}{7} =31.143$

So variance of the given data = 31.143

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2 years ago