Answer:
Explanation:
Define the purpose of the survey.
Make every question count.
Keep it short and simple.
Ask direct questions.
Ask one question at a time.
Avoid leading and biased questions.
Answer:
5.6 mm
Explanation:
Given that:
A cylindrical tank is required to contain a:
Gage Pressure P = 560 kPa
Allowable normal stress = 150 MPa = 150000 Kpa.
The inner diameter of the tank = 3 m
In a closed cylinder there exist both the circumferential stress and the longitudinal stress.
Circumferential stress
Making thickness t the subject; we have
t = 0.0056 m
t = 5.6 mm
For longitudinal stress.
t = 0.0028 mm
t = 2.8 mm
From the above circumferential stress and longitudinal stress; the stress with the higher value will be considered ; which is circumferential stress and it's minimum value with the maximum thickness = 5.6 mm
Answer:
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Explanation:
Answer : The crystal structure of Rhodium is, FCC (Z=4)
Explanation :
Nearest neighbor distance, r = 0.1345nm=1.345\times 10^{-8}cm (1nm=10^{-7}cm)
Atomic mass of rhodium (M) = 102.9 g/mole
Avogadro's number
First we have to calculate the cubing of edge length of unit cell for BCC and FCC crystal lattice.
For BCC lattice :
For FCC lattice :
Now we have to calculate the density of unit cell for BCC and FCC crystal lattice.
Formula used :
.............(1)
where,
= density
Z = number of atom in unit cell (for BCC = 2, for FCC = 4)
M = atomic mass
= Avogadro's number
a = edge length of unit cell
Now put all the values in above formula (1), we get
From this information we conclude that, the given density is approximately equal to the density of FCC unit lattice.
So, the crystal structure of Rhodium is, FCC (Z=4)