Dicotyledonous plants
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Answer:
44. (C) The temperature must decrease because the reaction is endothermic
45. (D) 3Pi
46. (C) It must be positive since positive since ΔG° is positive and ΔH° is positive
47. (B) The sum of the bond enthalpies of the bonds of the reactant is less than the sum of the bond enthalpies of the bonds of the products
Explanation:
Here we have
CH₃OH(g) → CO(g) + 2H₂(g) ΔH° +91 kJ/mol
44. Since the reaction is endothermic, absorbs heat, temperature must decrease because the reaction is endothermic
45. Since the number of moles in the reactant is 1 and the number of moles in the product is 3, we have;
Pressure, P is directly proportional to the number of moles
Therefore, where the pressure in the reactant is Pi pressure in the products will be 3Pi
46 Since the reaction takes place spontaneously at 600 K, therefore ΔG is negative and ΔH is positive hence ΔS must be positive
47. Since the reaction is an endothermic reaction, the sum of the bond enthalpies of the bonds of the reactant is less than the sum of the bond enthalpies of the bonds of the products.