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statuscvo [17]
4 years ago
9

In a tissue type that undergoes a relatively great deal of mechanical stress, like the tissue that lines the intestine, you woul

d expect to see an abundance of ________ between the individual cells of the tissue.
Chemistry
1 answer:
rewona [7]4 years ago
7 0

Answer:

Desmosomes.

From what I remember from my science class.

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Whats the formula for density
Sergio039 [100]

p =\frac{m}{V}

<em>p equals m over V</em>

hope this helps!!

7 0
3 years ago
Read 2 more answers
The answer to the multiple choice question
GenaCL600 [577]
The answer is A but i'm not sure .
3 0
3 years ago
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2) What is the concentration of NaCl in a solution prepared by diluting 56.98 ml of 0.5894 M stock
RSB [31]

Answer:

The NaCl concentration will be 0.03 M.

Explanation:

Given data:

Initial volume = V₁ = 56.98 mL (56.98/1000 = 0.05698 L)

Initial concentration = M₁= 0.5894 M

Final volume = V₂= 1.20 L

Final concentration = M₂= ?

Solution:

By diluting the solution volume of solution will increase while number of moles of solute remain the same.

Formula:

Initial concentration × Initial volume  = Final concentration × Final volume

M₁V₁ = M₂V₂

M₂ = M₁V₁ / V₂

M₂ = 0.5894 M × 0.05698 L / 1.20 L

M₂ = 0.0336 M /1.20  

M₂ = 0.03 M

3 0
4 years ago
Many important biochemicals are organic acids, such as pyruvic acid ( p K a = 2.50 ) and lactic acid ( p K a = 3.86 ) . The conj
Ivenika [448]

Answer:

Pyruvic acid: conjugate base

Lactic acid: conjugate base

Explanation:

The ratio of conjugate base to conjugate acid can be found using the Henderson-Hasselbalch equation when the pH and pKa are known.

pH = pKa + log([A⁻]/[HA])

The equation can be rearranged to solve for the ratio:

pH - pKa = log([A⁻]/[HA])

[A⁻]/[HA] = 10^(pH-pKa)

Now we can calculate the ratio for the pyruvic acid:

[A⁻]/[HA] = 10^(pH-pKa) = 10^(7.4 - 2.50) = 79433

[A⁻] = 79433[HA]

There is a much higher concentration of the conjugate base.

Similarly for lactic acid:

[A⁻]/[HA] = 10^(pH-pKa) = 10^(7.4 - 3.86) = 3467

[A⁻] = 3467[HA]

For lactic acid the conjugate base also dominates at pH 7.4

6 0
4 years ago
4.0 mol Na2S reacts with 5.0 mol
Bumek [7]

The number of moles of Na_2SO_4 form from 5.0 moles Na_2S is 5 moles.

<h3>What is a limiting reactant?</h3>

Limiting reactants are those reactants that are completely used up in a chemical reaction.

4.0 mol Na_2S will be completely used since the combining ratio is 1 : 1 : 1.

Na_2S + CuSO_4 ->Na_2SO_4 + CuS

From the chemical equation above, 5.0 moles Na_2S will yield 5 moles of Na_2SO_4.

Learn more about limiting reactants here:

brainly.com/question/14222359

#SPJ1

5 0
2 years ago
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