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lidiya [134]
3 years ago
11

Can at transform plate boundaries, two plate move toward each other true or false

Physics
1 answer:
nekit [7.7K]3 years ago
7 0
 the answer to the question is false

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To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

We know that:

V = 3.6 V is the voltage applied

I = 2.6 A is the current

So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

t = 350 s

Therefore, the energy supplied is

E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

where in this problem:

E = 3276 J is the energy supplied

C is the heat capacity of the object

\Delta T =29.1^{\circ}-20.3^{\circ}=8.8^{\circ}C is the change in temperature

Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
3 years ago
Which is the electric potential energy of a charged particle divided by its charge?Electric fieldelectric field lineelectric pot
Dahasolnce [82]
<h3><u>Answer;</u></h3>

electric potential

<h3><u>Explanation;</u></h3>

Electric potential is the electric potential energy per unit charge.

Mathematically; V =PE/q

Where; PE is the electric potential energy, V is the electric potential and q is the charge.

Electric potential is more commonly known as voltage.  If you know the potential at a point, and you then place a charge at that point, the potential energy associated with that charge in that potential is simply the charge multiplied by the potential.

7 0
3 years ago
Total these measurements. Your answer should indicate the proper accuracy. Be sure to include the units in your answer. (Remembe
Mila [183]
Your answer is 8. You add 2 + 1 + 5.3 to get 8.3. You round down to 8 because of the sig fig rules.
5 0
3 years ago
One disadvantage of using proprietary licensed software is that
Vaselesa [24]

Answer:

its b

Explanation:

5 0
3 years ago
Read 2 more answers
A 10 kg cart is rolling across a parking lot with a velocity of .5 m/s. What is its momentum?
-Dominant- [34]

Hello!

\large\boxed{p = 5  \text{ } kgm/s}

Use the equation for momentum:

p = mv

Plug in the given mass and velocity into the equation:

p = 10 * 0.5

p = 5 kgm/ s

4 0
3 years ago
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