4. What is an oscillatory motion? Give examples.

Chemistry

1 answer:

Sloan [31]4 years ago

4 0

Answer:

an oscillator motion is a type of periodic motion ( ex. strings vibrating, swinging of a swing)

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200 ml is 1/5 of a liter, so the answer is five times the number of moles present in the solution. 0.6 moles/0.2 liter = x moles/1.0 liter. Solving for x gives 0.2 x = 0.6 or x = 3.0 M

so the answer is c

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What occurs at transform boundary faults and can cause tremendous devastation

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Earthquakes happen at Transform boundaries

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A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 8.5 oz . aluminum has a density of 2.70 g/cm3. w

Serhud [2]

Hello!

We have the following data:

Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)

To move on, we must transform the area of 50 ft² in cm², let's see:

1 ft² ------- 929,0304 cm²
50 ft² ----- A

$A = 50*929,0304$

$\boxed{A = 46451,52\:cm^2}\Longleftarrow(Area)$

In the same way, we will convert the mass of 8.5 oz in grams, see:

1 oz -------- 28,3495 g
8,5 oz ------- m

$m = 8,5*28,3495$

$\boxed{m = 240,97075\:g}\Longleftarrow(mass)$

Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:

$d = \dfrac{m}{V} \to V = \dfrac{m}{d}$

$V = \dfrac{240,97075\:\diagup\!\!\!\!\!g}{2,70\:\diagup\!\!\!\!\!g/cm^3}$

$V = 89,24842593... \to \boxed{V \approx 89,25\:cm^3}$

The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)

In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:

$V (volume) = A (Area) * T (Thickness)$

$89,25\:cm^3 = 46451,52\:cm^2\:*\:T$

$46451,52\:cm^2*T = 89,25\:cm^3$

$T = \dfrac{89,25\:cm^3}{46451,52\:cm^2}$

$T = 0,001921358009...\:cm$

We will convert to millimeters, going through a decimal place on the right

$T = 0,01921358009..\:mm$

$\boxed{\boxed{T \approx 0,0192\:mm\:or\:T\approx \:1,92*10^{-2}\:mm}}\end{array}}\Longleftarrow(thickness)\qquad\checkmark$

Hope this helps! :))

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0.315 to scientific notation

irga5000 [103]

Answer:

3.15 × 10^-1

3.15E-1

Explanation:

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