Answer:
1: A.) adapted
2: A.) habitat destruction
Explanation:
Some (few) animals are capable of adjusting their behaviors in relation to human activity and the changes humans make in their habitat. Most are so well adapted to the details of their habitat that they are incapable of surviving when those details change.
"Because all organisms are <u>adapted</u> to their native habitat, human activities that result in <u>habitat destruction</u> are a major reason for their extinction."
_____
<em>Comment on human activities</em>
My friendly local rodent exterminator observed that rodent activity has picked up substantially, since so much human activity has been curtailed by quarantine orders.
Answer:
<em>the last option!!!!</em>
Explanation:
because its right
Answer:
2M
Explanation:
M=mol/L
1. Find moles of CoCl2
mass of substance/molar mass = 130/129.833 = 1.001 mol
3. Substitute in molarity equation
M=(1.001/0.5)
M= around 2M
Answer:
Explanation:
Industrial examples
Process Reactants, Product(s)
Ammonia synthesis (Haber–Bosch process) N2 + H2, NH3
Nitric acid synthesis (Ostwald process) NH3 + O2, HNO3
Hydrogen production by Steam reforming CH4 + H2O, H2 + CO2
Ethylene oxide synthesis C2H4 + O2, C2H4O
Taking into account the stoichiometry of the reaction, 34.12 grams of LiOH are produced from 9.89 g of Li.
In first place, the balanced reaction is:
2 Li + 2 H₂O ⇒ 2 LiOH + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Li= 2 moles
- H₂O= 2 moles
- LiOH= 2 moles
- H₂= 1 mole
The molar mass of each compound is:
- Li= 6.94 g/mole
- H₂O= 18 g/mole
- LiOH= 23.94 g/mole
- H₂= 2 g/mole
By reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:
- Li= 2 moles× 6.94 g/mole= 13.88 g
- H₂O= 2 moles× 18 g/mole= 36 g
- LiOH= 2 moles× 23.94 g/mole= 47.88 g
- H₂= 1 mole× 2 g/mole= 2 g
Then you can apply the following rule of three: if by reaction stoichiometry 13.88 g of Li produce 47.88 g of LiOH, 9.89 g of Li produce how much mass of LiOH?
Solving:
<u><em>mass of LiOH= 34.12 grams</em></u>
Finalli, 34.12 grams of LiOH are produced from 9.89 g of Li.
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