What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?
1 answer:
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Answer:
The volume of the cavity is 0.013m^3
Explanation:
To find the volume of the cavity, the major parameter missing is the diameter of the cavity itself. we can obtain this using the following steps:
Step one:
Obtain the volume of the cylinder by dividing the mass of the cylinder by the density.
Volume of the cylinder = 2.1 / 11.053 =0.19
Step two:
From the volume of the cylinder, we can get the radius of the cylinder.
Step three:
From the cross-sectional area, we can obtain the radius of the cavity.
Let the radius of the cavity be = r, while the radius of the cylinder be = R
CSA of cavity =
Step Four:
calculate the volume of the cavity using volume =
Recall that the cavity has the same height as the original cylinder
Answer:
841.5 Hz
Explanation:
Given
y = 50 cm = 0.5 m
d = 5.00 m
L = 12.0 m away from the wall
v = speed of sound = 343 m/s
The image of the scenario is presented in the attached image.
When destructive interference is being experienced from 50 cm (0.5 m) parallel to the wall, the path difference between the distance of the two speakers from the observer is equal to half of the wavelength of the wave.
Let the distance from speaker one to the observer's new position be d₁
And the distance from the speaker two to the observer's new position be d₂
(λ/2) = |d₁ - d₂|
d₁ = √(12² + 3²) = 12.3693 m
d₂ = √(12² + 2²) = 12.1655 m
|d₁ - d₂| = 0.2038 m
(λ/2) = |d₁ - d₂| = 0.2038
λ = 0.4076 m
For waves, the velocity (v), frequency (f) and wavelength (λ) are related thus
v = fλ
f = (v/λ) = (343/0.4076) = 841.5 Hz
Hope this Helps!!!
