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dmitriy555 [2]
2 years ago
12

Please help ASAP list three intermolecular forces from strongest to weakest

Chemistry
2 answers:
garri49 [273]2 years ago
7 0

Answer: There are three different types of intermolecular forces in terms of strength. They are (strongest to weakest) hydrogen bonding, dipole-dipole and Van der Waals' forces.

Explanation: Mark me brain, give 5 stars and a thank you

Yanka [14]2 years ago
7 0

Answer:

hydrogen bonding, dipole-dipole and Van der Waals' forces.

Explanation:

hope this helps

plz hit the thanks button

plz mark 5 stars

plz mark brainliest

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Hydrogen peroxide is a powerful oxidizing agent; it is used in concentrated solution in rocket fuel and in dilute solution in ha
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The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

Co = 10pd/M

Where;

Co = concentration = ?

p = percent of the hydrogen peroxide =  30%

d = Density of hydrogen peroxide =  1.39 g/ml

M = Molar mass  = 34 g/mol

Substituting values;

Co = 10 × 30 ×  1.39/34

Co = 12.26 M

The molarity of the hydrogen peroxide solution from the information supplied in the question is 12.26 M.

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Which energy change occurs during boiling?
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Heat energy is absorbed by the substance.
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Which process represents a chemical change?(1) melting of ice(2) corrosion of copper(3) evaporation of water(4) crystallization
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(2) Corrosion of copper.
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3 years ago
Rutherford used a gold foil experiment and discovered what part of an atom
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Consider a solution prepared by mixing the following:50.0 mL of 0.100 M Na3PO4100.0 mL of 0.0500 M KOH200.0 mL of 0.0750 M HCl50
Juliette [100K]

Answer:

you must add 50 mL

Explanation:

Hi

KOH is a strong base and by adding 100mL 0.05M you will have an amount of 5 millimol.

NaCN is a base and by adding 50 mL 0,150 M you will have an amount of 7,5 mmol.

HCl is a acid and by adding 200 mL 0,075 M you will have an amount of 15 mmol.

The acid reacts with the bases leaving 2.5 mmol unreacted.

Na3PO4 is a base and by adding 50 mL 0,1 M you will have an amount of 5 mmol.

The 2.5 mmol of acid react with the base PO4 ^ -3 forming a regulatory solution of PO4 ^ -3 and HPO4 ^ -2 of pKa 2.12

5 mmol of acid (HNO3) must be added to obtain a regulatory solution formed by the same amount of HPO4 ^ -2 (2.5 mmol) and H2PO4 ^ -1 (2.5 mmol) with pKa 7.21

Considering a quantity of 5 mmol of HNO3 of concentration 0.1 M, 50 mL must be added.

To calculate the pH of the regulatory solution you should consider pH = pKa × Ca / Cb pH = 7.21 × 2.5 / 2.5 = 7.21 Being in the same solution the volume is the same and can be simplified to achieve a faster calculation.

successes with your homework

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