<u>Given:</u>
Temperature T = 0.20 μK
<u>To determine:</u>
The de Broglie wavelength of Rubidium atoms
<u>Explanation:</u>
The de broglie wavelength (λ) is related to the temperature (T) as:
λ = h/√2πmkT -----(1)
where h = Planck's constant = 6.626*10⁻³⁴ Js
m = mass of Rubidium = 85.47 amu * 1.66*10⁻²⁷ kg/ 1 amu = 1.419*10⁻²⁵ kg
k = Boltzmann constant = 1.38*10⁻²³ J.K⁻¹
T = temperature = 0.2 μK = 0.2 *10⁻⁶ K
Substituting these values in equation (1) we get:
λ = 6.626*10⁻³⁴ Js/√2π * 1.419*10⁻²⁵ kg * 1.38*10⁻²³ J.K⁻¹ * 0.2 *10⁻⁶ K
= 4.224*10⁻⁷ m
Ans: The de Broglie wavelength is 4.224*10⁻⁷ m
Whatever depends on the voltage would change very quickly i guess
Answer:
<h2>Rotational inertia first decreases and then increases as the satellite is ready to land</h2>
Explanation:
This problem is based on the conservation of angular momentum.
<h2>What is the Law of Conservation of Angular Momentum
?</h2>
The Law of Conservation of Angular Momentum states that
<em>"The angular momentum of a system of particles around a point in a fixed inertial reference frame is conserved if there is no net external torque around that point".</em>
The rate of rotation increases greatly when the Satelite is moved inwards by 10%, decreasing the moment of inertia. The work-done to pull in the Satelite results in an increase in rotational kinetic energy.