Calculate the potential required to push eleven amperes through a 20 ohm resistance
2 answers:
You might be interested in
Answer:
The value is
Explanation:
From the question we are told that
The power rating of the stove is
The duration of its use everyday is
The rating of the light bulbs is
The number is
The power rating of the total bulb is
The duration of its use everyday is
The power rating of miscellaneous appliance
The duration of its use everyday is
The power rating of hot water
The duration of its use everyday is
Generally the total electrical energy used in 1 month is mathematically represented as
=>
=>
=>
Generally the monthly electricity bill is mathematically represented as
=>
Answer:
= 0.331 J / g ° C
Explanation:
We have a calorimetry exercise where all the heat yielded by one of the components is absorbed by the other.
Heat ceded Qh = m1 ce1 ( -
)
Heat absorbed Qc = m2 ce2 ( - T₀)
Body 1 is metal and body 2 is water . Where m are the masses of the two bodies, ce their specific heat and T the temperatures
Qh = Qc
m₁ (
-
) = m₂
(
- T₀)
we clear the specific heat of the metal
= m₂
(
- T₀) / (m₁ (
-
))
= 50.00 4.184 (20.15 -10.79) / (75.00 (99.0-20.15))
= 209.2 (9.36) / (75 78.85)
= 1958.11 / 5913.75
= 0.331 J / g ° C
Answer:
The the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.
Explanation:
Given;
mass of bullet, m₁ = 4.2 g = 0.0042 kg
mass of hunter + gun = 72.5 kg
velocity of the bullet, u = 965 m/s
Momentum of the bullet when it was fired;
P = mv
P = 0.0042 x 965
P = 4.053 kg.m/s
Determine the recoil velocity of the hunter.
Total momentum = sum of the individual momenta
Total momentum = momentum of the bullet + momentum of the hunter
Apply the principle of conservation of momentum, sum of the momentum is equal to zero.
Therefore, the the recoil velocity of the hunter is 0.056 m/s in opposite direction of the bullet.