According to Ptolemy's model, he, too, believed in a geocentric Universe and that the planets and stars were perfect spheres, though Earth itself was not.
He further thought that the movements of the planets and stars must be circular since they were perfect and, if the motions were circular, then they could go on forever.
<h3>What is comets and shooting stars?</h3>
Shooting stars are very different from comets, although the two can be related. A Comet is a ball of ice and dirt, orbiting the Sun (usually millions of miles from Earth). ... A shooting star on the other hand, is a grain of dust or rock (see where this is going) that burns up as it enters the Earth's atmosphere.
Learn more about ptolemy's model:
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I really dont know you would do that yourself soo yea..,
Explanation:
Each resistor has a resistance of R.
In the first problem, each row of three resistors in series has a resistance or 3R.
A₂ = 4A, so the voltage drop across the rows is:
V = IR
V = (4)(3R)
V = 12R
The voltage drop equals the voltage gain (Kirchoff's voltage law). The battery has a voltage of 9V, so:
9 = 12R
R = 0.75 Ω
The three rows are in parallel with each other, so the total resistance is:
∑R = (1/(3R) + 1/(3R) + 1/(3R))⁻¹
∑R = R
∑R = 0.75 Ω
The current A₁ can be found with Ohm's law:
V = IR
9 = (A₁) (0.75)
A₁ = 12 A
Using Ohm's law to find V₁, V₂, and V₃:
V = IR
V₁ = (4)(0.75)
V₁ = 3V
V₂ = (4)(2×0.75)
V₂ = 6 V
V₃ = (4)(3×0.75)
V₃ = 9 V
In the second problem, all the resistors are in series. So the total resistance is:
∑R = 8R
The battery voltage is 16V, and A₂ = 6A. So using Ohm's law:
V = IR
16 = (6)(8R)
R = 1/3 Ω
Since there's only one loop, the current is the same at all points. So A₁ = A₂ = 6A.
Using Ohm's law to find each voltage:
V = IR
V₁ = (6)(1/3)
V₁ = 2V
V₂ = (6)(2×1/3)
V₂ = 4 V
V₃ = (6)(4×1/3)
V₃ = 8 V
V₄ = (6)(2×1/3)
V₄ = 4 V
Answer:
2.7 x 10^-14 m
Explanation:
E =8.8 MeV = 8.8 x 1.6 x 10^-13 J
q = 2 e = 2 x 1.6 x 10^-19 C
Q = 82 e = 82 x 1.6 x 10^-19 C
Let d be the distance of closest approach
E = k Q q / d
Where, K = 9 x 10^9 Nm^2 / C^2
d = k Q q / E
d = (9 x 10^9 x 82 x 1.6 x 10^-19 x 2 x 1.6 x 10^-19) / (8.8 x 1.6 x 0^-13)
d = 2.7 x 10^-14 m
Answer:
<em>Physical change is a temporary change. A chemical change is a permanent change</em>
<em>examples of physical change are freezing of water, melting of wax, boiling of water, etc. A few examples of chemical change are digestion of food, burning of coal, rusting, etc.</em>
<h3>
I HOPE THIS WILL HELP YOU</h3>
HAVE A GREAT DAY :)