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Anna [14]
3 years ago
13

A camera lens focuses on an object 75.0 cm from the lens. The image forms 3.50 cm behind the lens. What is the magnification of

the image?
Physics
1 answer:
Yakvenalex [24]3 years ago
5 0

Answer:

Explanation:

Refraction by a Convex Lens

Refraction bends the light downward upon entering the glass because the bottom part of the ray hits the slow medium first.

Light travels more slowly in glass than in air. The amount of bending depends upon the index of refraction of the glass.

Image formation depends upon bending light rays with lenses.

Refraction bends the light downward again upon leaving the glass because the top part of the ray hits the faster medium first.

Index

Lens concepts

 

HyperPhysics***** Light and Vision R Nave

Go Back

Magnification:Transverse &Angular

The linear magnification or transverse magnification is the ratio of the image size to the object size. If the image and object are in the same medium it is just the image distance divided by the object distance.

Using the Gaussian form of the lens equation, a negative sign is used on the linear magnification equation as a reminder that all real images are inverted. If the image is virtual, the image distance will be negative, and the magnification will therefore be positive for the erect image.

If the media are different on the two sides of the surface or lens, the magnification is not quite so straigtforward. It can be variously expressed as

In this equation V is the vergence, n is the index of refraction, and u is used for the angle. Note that in this expression for the magnification, the minus sign doesn't appear. In this type of setting, the Cartesian sign convention is typically used and the object distance has a negative value. That takes care of the minus sign that is put in above in the Gaussian form.

The angular magnification of an instrument is the ratio of the angle subtended at the eye when using the instrument divided by the angular size without the instrument. An important example is the simple magnifier. The angular magnification of any optical system can be obtained from the system matrix for the system.

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If 31.25
valentina_108 [34]
<span>1 C = 6.24150965(16)×10^18 electrons

31.25 x 10^18 electrons / (6.24150965(16)×10^18 electrons / C) = 5.007 Coulombs

</span><span>I hope this helps. </span>
4 0
3 years ago
Read 2 more answers
Three beads are placed on the vertices of an equilateral triangle of side d = 3.4cm. The first bead of mass m1=140gis placed on
Vlad [161]

Answer:

Xcm = 1.95 cm  and Ycm = 1.76 cm

Explanation:

The very useful concept of mass center is

     R cm = 1/M  ∑ m_{i}  r_{i}

Where ri, mi are the mass positions of the bodies from some reference point by selecting and M is the total mass of the body.

Let's look for the total mass

     M = m₁ + m₂ + m₃

     M = 140 + 45 + 85

     M = 270 g

Let's look for the position of each point

Point 1. top vertex, if the triangle has as side d

      R₁ = d / 2 i ^ + d j ^

      R₁ = (1.7 cm i ^ + 3.4 j ^) cm

Point 2. left vertex. What is the origin of the system?

      R₂ = 0

Point 3. Right vertex

      R₃ = d i ^

      R₃ = 3.4 i ^ cm

a) The x component of the massage center

      Xcm = 1 / M (m₁ x₁ + m₂ x₂ + m₃ x₃)

      Xcm = 1 / M (m₁ d / 2 + 0 + m₃ d)

      Xcm = d / M (m₁ / 2 + m₃)

b)   Let's write the mass center component x

      Xcm = 1/270 (1.7 140 + 0 + 3.4 85)

      Xcm = 238/270

      Xcm = 1.95 cm

c) let's find the component and center of mass

     Ycm = 1 / M (m₁ y₁ + m₂ y₂ + m₃ y₃)

    Ycm = 1 / M (m₁ d + 0 + 0)

    Ycm = m₁ / M d

d) let's calculate

    Y cm = 1/270 (140 3.4 + 0 + 0)

    Ycm = 1.76 cm

8 0
4 years ago
Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record w
Scorpion4ik [409]

Answer:

Explanation:

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

Writers periodically compete to see who can write the longest sentence in literature. James Joyce long held the English record with a 4,391 word sentence in Ulysses. Jonathan Coe one-uped him in 2001 with a 13,955 word sentence in The Rotter’s Club. More recently, a single-sentence, 469,375 word novel appeared.

8 0
3 years ago
An airplane cabin is pressurized to 570 mmhg. what is the pressure inside the cabin in atmospheres?
abruzzese [7]
1 atm corresponds to 760 mmHg, so we can set up a simple proportion to find how many atmospheres correspond to 570 mmHg:
1 atm: 760 mmHg = x: 570 mmHg
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8 0
3 years ago
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9.58 A spring of equilibrium length L1 and spring constant k1 hangs from the ceiling. Mass m1 is suspended from its lower end. T
andrey2020 [161]

Answer:

The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.

See attachment below for full solution

Explanation:

This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.

4 0
4 years ago
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