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mash [69]
3 years ago
12

Help please maths please

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
4 0
Im not very good at math so i apologize
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Dean's class took a field trip to the art museum. They left school at 11:45 A.M. It took them 45 minutes to drive to the museum.
NikAS [45]

Answer:

2:00 p.m.

Step-by-step explanation:

driving to the museum is 12:30

then they sped 1 hour and 30 minutes

8 0
4 years ago
Express the polynomial below in the form P(x) = (x - k) times the quotient plus the remainder for the given value of k. P(x) = 3
Sergeu [11.5K]

Answer: ( X- k )(3x2 - 4x + 7) + 1

Step-by-step explanation: Please find the attached files for the solution

4 0
3 years ago
Read 2 more answers
Betty saves 3 times as much as Ann. Charles save 390 less than Ann.. If Betty saves save 1330 more than Charles. how much does C
Igoryamba

Answer:

80

Step-by-step explanation:

We let x be Ann's savings.

Betty saves 3 times as much as Ann.

This implies that Betty's savings in terms of x

= 3x

Charles save 390 less than Ann.

This implies Charles savings

= x - 390

Betty saves 1330 more than Charles.

This implies that when we deduct Charles savings from Betty's we have to get 1330.

Mathematical equation for the problem:

3x - (x - 390) = 1330

Expand :

\implies 3x - x  + 390= 1330

\implies 2x + 390= 1330

Subtract 390 from both sides.

\implies 2x + 390 - 390= 1330 - 390

\implies 2x=940

Divide through by 2

\implies \frac{2x}{2} = \frac{940}{2}

\implies x=470

Hence Charles saving is

x - 390 = 470 - 390 = 80

7 0
4 years ago
A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9^
MrRa [10]

Correct question is;

A football is kicked up into the air. Its height, H, above the ground, in meters, at t seconds can be modelled by () = 24 − 4.9²

(a) Determine the expression for the instantaneous rate of change in height at time t.

(b) Determine ' (2) What does ' (2) represent?

Answer:

A) '() = 24 − 9.8

B) '(2) = 4.4 m/s

It means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s

Step-by-step explanation:

We are given the function to represent the height as;

() = 24 − 4.9²

A) expression for the instantaneous rate of change in height at time t will be gotten by differentiation of the height function. Thus;

'() = 24 − 9.8

B) '(2) = 24 - 9.8(2)

'(2) = 4.4 m/s

This means that at a distance of 2 m above the ground, the speed of the ball is 4.4 m/s

7 0
3 years ago
4. The ordered pair (-2,-1) is a solution to which
ioda

C

4(-2) - y = -7

-8 -y = -7

-y =-7 +8

y= -1

8 0
3 years ago
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