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3 years ago

Is castor oil good to reduce wrinkles

1 answer:

6 0

Castor oil contains fatty acids that have moisturizing, skin health-enhancing, and antioxidant properties. These fatty acids may also help minimize wrinkles. Castor oil also has emollient properties known to help improve your skin's texture and healthy appearance.

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Water evaporating from a puddle is an example of a

Flauer [41]

It is an example of physical change. The molecules are not changing, so it is not chemical, and a physical property is something that a physical thing has.

5 0

4 years ago

Read 2 more answers

The atomic number of oxygen is 8 which indicates that there are 8

Zinaida [17]

Answer:

Protons

Explanation:

3 0

3 years ago

Based on this reaction, find how many moles of co can be obtained starting with 7 mol ch4?

Klio2033 [76]

I will solve the question assuming the reaction used as below
1 CH4(g) + 1 H2O(g) ==> 1 CO(g) + 3 H2(g)

In the reaction, CH4 is the reactant and CO is the wanted product. If you look at the coefficient of the substance, for every 1 mol of CH4 react there will be 1 mol of CO produced. So, if you have 7 moles of CH4 the amount of CO produced would be: 7 moles * 1/1= 7 moles of CO

5 0

4 years ago

Read 2 more answers

If 83.6 grams of H2 and 257 grams of N2 react, how many grams of ammonia will be produced?

SSSSS [86.1K]

The mass of ammonia that would be produced is 312.5 g

First, we will write a balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

3H₂(g) + N₂(g) → 2NH₃(g)

This means

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas to produce 2 moles of ammonia.

First, we will determine the number of moles of each reactant present

For Hydrogen (H₂)

Mass = 83.6 g

Molar mass = 2.016 g/mol

Using the formula

$Number\ of\ moles = \frac{Mass}{Molar\ mass}$

Number of moles of H₂ present = $\frac{83.6}{2.016}$

∴ Number of moles of H₂ present = 41.468254 moles

For Nitrogen (N₂)

Mass = 257 grams

Molar mass = 28.0134 g/mol

∴ Number of moles of N₂ present = $\frac{257}{28.0134}$

Number of moles of N₂ present = 9.174181 moles

Since,

3 moles of hydrogen gas reacts with 1 mole of nitrogen gas to produce 2 moles of ammonia

Then,

27.522543 moles of hydrogen gas will react with the 9.174181 moles of nitrogen gas to produce 18.348362 moles of ammonia

∴ 18.348362 moles of ammonia will be produced during the reaction

Now, for the mass of ammonia that would be produced

From the formula

Mass = Number of moles × Molar mass

Molar mass of ammonia = 17.031 g/mol

Mass of ammonia that would be produced = 18.348362 × 17.031

Mass of ammonia that would be produced = 312.49095 g

Mass of ammonia that would be produced ≅ 312.5 g

Hence, the mass of ammonia that would be produced is 312.5 g

Learn more here: brainly.com/question/13902065

3 0

3 years ago

Calculate the number of milliliters of 0.666 M Ba(OH)2 required to precipitate all of the Pb2 ions in 163 mL of 0.656 M Pb(NO3)2

Sliva [168]

Answer:

161 mL

Explanation:

Pb(NO₃)₂(aq) + Ba(OH)₂(aq) → Pb(OH)₂(s) + Ba(NO₃)₂(aq)

First we calculate how many Pb⁺² moles reacted, using the given concentration and volume of the Pb(NO₃)₂ solution:

163 mL * 0.656 M = 107 mmol Pb(NO₃)₂

As 1 millimol of Pb(NO₃)₂ would react with 1 millimol of Ba(OH)₂, to precipitate 107 mmoles of Pb(NO₃)₂ we would require 107 mmoles of Ba(OH)₂.

Using the number of moles and the concentration we can calculate the required number of milliliters:

0.666 M = 107 mmol / x mL

x mL = 161 mL

5 0

3 years ago