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2 years ago

12

One of the flaws in the engineers' reasoning for galloping gertie's design was that they attributed prior failures of suspension

bridges to too much weight or poor workmanship.
True or false

1 answer:

Jlenok [28]2 years ago

3 0

False i think it would be

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The human circulatory system consists of a complex branching pipe network ranging in diameter from

Stels [109]

Answer: the average velocity decreases

Explanation:

From the provided data we have:

Vessel avg. diameter[mm] number

Aorta 25.0 1

Arteries 4.0 159

Arteioles 0.06 1.4*10^7

Capillaries 0.012 2.9*10^9

from the information, let $\hat{m}$ be the mass flow rate, $\rho$ is density, n number of vessels, and A is the cross-section area for each vessel

the flow rate is constant so it is equal for all vessels,

The average velocity is related to the flow rate by:

$\hat{m} = v* \rho * A * n$

we clear the side where v is in:

$v = \frac{\hat{m}}{\rho A n}$

area is π*R^2 where R is the average radius of the vessel (diameter/2)

we get:

$v = \frac{\hat{m}}{\rho \pi R^2 n}$

you can directly see in the last equation that if we go from the aorta to the capillaries, the number of vessels is going to increase ( n will increase and R is going to decrease ) . From the table, R is significantly smaller in magnitude orders than n, therefore, it wont impact the results as much as n. On the other hand, n will change from 1 to 2.9 giga vessels which will dramatically reduce the average blood velocity

8 0

3 years ago

Which is a better hydraulic cross section for an open channel: one with a small or a large hydraulic radius?

Cerrena [4.2K]

Hydraulic radius is caused by pressurized hydrogen air so that should mean the answer is hydraulic radius

6 0

2 years ago

6.Identification of Material ParametersThe principal in-plane stresses and associated strains in a plate of material areσ1= 50 k

ad-work [718]

Answer:

See attached image for diagrams and solution

6 0

2 years ago

Thin film deposition is a process where: a)-elemental, alloy, or compound thin films are deposited onto a bulk substrate! b)-Pho

marshall27 [118]

Answer:

(A) elemental, alloy, or compound thin films are deposited on to a bulk substrate

Explanation:

In film deposition there is process of depositing of material in form of thin films whose size varies between the nano meters to micrometers onto a surface. The material can be a single element a alloy or a compound.

This technology is very useful in semiconductor industries, in solar panels in CD drives etc

so from above discussion it is clear that option (a) will be the correct answer

8 0

3 years ago

A 0.19-m3 rigid tank equipped with a pressure regulator contains steam at 2 MPa and 300°C. The steam in the tank is now heated.

AVprozaik [17]

Answer:

576.21kJ

Explanation:

#We know that:

The balance mass $m_{in}+m_{out}=\bigtriangleup m_{system}$

so, $m_e=m_1-m_2$

$Energy \ Balance\\E_{in}-E_{out}=\bigtriangleup E_{system}\\\\\therefore Q_i_n+m_eh_e=m_2u_2-m_1u_1$

#Also, given the properties of water as;

$(P_1=2Mpa,T_1=300\textdegree C)->v_1=0.12551m^3/kg,u_1=2773.2kJ/kg->h_1=3024.2kJ/kg\\\\(P_2=2Mpa,T_1=500\textdegree C)->v_2=0.17568m^3/kg,u_1=3116.9kJ/kg->h_1=3468.3kJ/kg$

#We assume constant properties for the steam at average temperatures: $h_e=\approx(h_1+h_2)/2$

#Replace known values in the equation above; $h_e=(3024.2+3468.3)/2=3246.25kJ/kg\\\\m_1=V_1/v_1=0.19m^3/(0.12551m^3/kg)=1.5138kg\\\\m_2=V_2/v_2=0.19m^3/(0.17568m^3/kg)=1.0815kg$

#Using the mass and energy balance relations;

$m_e=m_1-m_2\\\\m_e=1.5138-1.0815\\\\m_e=0.4323kg$

#We have $Q_i_n+m_eh_e=m_2u_2-m_1u_1$ : we replace the known values in the equation as;

$Q_i_n+m_eh_e=m_2u_2-m_1u_1\\\\Q_i_n=0.4323kg\times3246.2kJ/kg+1.0815kg\times3116.9-1.5138kg\times2773.2kJ/kg\\\\Q_i_n=573.21kJ$

#Hence,the amount of heat transferred when the steam temperature reaches 500°C is 576.21kJ

5 0

3 years ago