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Whitepunk [10]
3 years ago
12

How can you differentiate the Atomic Structure and the Bohr Model? In other words, how is the Atomic Structure different from th

e Bohr Model)
Chemistry
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

Bohr thought that electrons orbited the nucleus in circular paths; whereas in the modern view atomic electron structure is more like 3D standing waves. Bohr built upon Rutherford's model of the atom. ... He believed that electrons moved around the nucleus in circular orbits with quantised potential and kinetic energies.

Explanation:

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A 15.0-L scuba diving tank contains a helium-oxygen (heliox) mixture made up of 23.0 g of He and 4.14 g of O2 at 298 K. Calculat
EleoNora [17]

<u>Answer:</u> The mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For helium:</u>

Given mass of helium = 23 g

Molar mass of helium = 4 g/mol

Putting values in equation 1, we get:

\text{Moles of helium}=\frac{23g}{4g/mol}=5.75mol

  • <u>For oxygen gas:</u>

Given mass of oxygen gas = 4.14 g

Molar mass of oxygen gas = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of oxygen gas}=\frac{4.14g}{32g/mol}=0.129mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For helium:</u>

Moles of helium = 5.75 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

\chi_{(He)}=\frac{5.75}{5.879}=0.978

  • <u>For oxygen gas:</u>

Moles of oxygen gas = 0.129 moles

Total moles = [5.75 + 0.129] = 5.879 moles

Putting values in above equation, we get:

\chi_{(O_2)}=\frac{0.129}{5.879}=0.022

Hence, the mole fraction of Helium is 0.978 and that of oxygen gas is 0.022

3 0
3 years ago
When ammonium carbonate decomposes what gas is produced and will a glowing splint burn brighter in the presence?
mestny [16]
When ammonium carbonate is heated it decomposes to give ammonia gas, carbon dioxide gas and water. The equation for the decomposition is;
(NH4)2CO3(s) = 2 NH3 (g) + CO2(g) + H2O(l)
A glowing splint would extinguish almost immediately because of the presence of carbon dioxide. Carbon dioxide does not support burning which is the property that makes it used a s a fighter extinguisher.
7 0
3 years ago
I need help with this pls
N76 [4]

Answer:

1)20 \\ 2)13 \\ 3)82 \\ 4)56 \\ 5)26 \\ 6)1 \\ hope \: it \: helps \\ plzzz \: mark \: it \: as \: brainliest...

3 0
3 years ago
What is the density (g/L) of 5.0 moles of NH3, at 1.18 atm and 25.0°C?
Goryan [66]
The answer will be 4667C
5 0
1 year ago
Read 2 more answers
What products would you expect from the reaction of ammonia and sulfuric acid in aqueous solution? 2nh3(aq)+h2so4(aq)→ ?
arsen [322]
From the reaction of ammonia and sulfuric acid in aqueous solution 2nh3(aq)+h2so4(aq)<span>→</span> (NH4)2SO4 + H2O will be formed.Sulfuric acid is diprotic so is able to give up 2 H+ ions. It is an acid-base neutralisation reaction forming ammonium sulphate as the salt. 2NH3 with H2SO4 reacts in a neutralization reaction to form salt water, with ammonium sulphate left behind to crystallize after evaporation.
5 0
3 years ago
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