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Whitepunk [10]
3 years ago
12

How can you differentiate the Atomic Structure and the Bohr Model? In other words, how is the Atomic Structure different from th

e Bohr Model)
Chemistry
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

Bohr thought that electrons orbited the nucleus in circular paths; whereas in the modern view atomic electron structure is more like 3D standing waves. Bohr built upon Rutherford's model of the atom. ... He believed that electrons moved around the nucleus in circular orbits with quantised potential and kinetic energies.

Explanation:

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My teacher is grading this soon can someone help me ASAP!
Stolb23 [73]

10. You demonstrated the difference in density of the two objects. It is a physical property.

11. First calculate the density for all of them: density = mass/volume

Density:

A. 5/6 g/ml

B. 10/9 g/ml

C. 15/16 g/ml

D. 20/10 g/ml

If the density of the substance is higher than the density of the substance it is put in, then it will sink. So substances B and D will sink in water, as their densities are higher than 1 g/ml.

12. Ammonia weighs less than water does-- for example, the weight of 8 gallons of ammonia will be equivalent to the weight of 5 gallons of water.

Hope this helped!

3 0
3 years ago
Plz help me I am timed
Eddi Din [679]

Answer:

C. interior plains

Explanation:

sana makatulong

8 0
2 years ago
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Which one of the following questions about animals called affairs, pictured above, is the scientific question?
tino4ka555 [31]

The answer is B...

because any of the others could have an opinion based answer but B will always be the same its a fact not opinion.

3 0
3 years ago
Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT
Andru [333]

Answer:

6.14\cdot 10^{-6}

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

K_{eq} = \frac{[ADP][Pi]}{ATP}

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

\Delta G^o = -RT ln K_{eq}

From here, rearrange the equation to solve for K:

K_{eq} = e^{-\frac{\Delta G^o}{RT}}

Now we know from the initial equation that:

K_{eq} = \frac{[ADP][Pi]}{ATP}

Let's express the ratio of ADP to ATP:

\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}

Substitute the expression for K:

\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}

Now we may use the values given to solve:

\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}

7 0
3 years ago
Do strong acid and strong base have similar effects on protein solubility and denaturation
mafiozo [28]
Both strong acid and strong base will alter the solubility and the nature of a protein. This is because, adding a strong acid or base to a protein will drastically change the pH of the protein and this will leads to formation of precipitation and denaturation of the protein.
7 0
3 years ago
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