All categories

3 years ago

A certain mass of gàs occupied 5.0dm cube at 2 atm and 10°C .calculate d no of moles present

Chemistry

1 answer:

zvonat [6]3 years ago

6 0

Answer: 0.43mol

Explanation:Please see attachment for explanation

You might be interested in

For an enzymatically catalyzed reaction in which the measured values for KM and Vmax are, respectively, 10.0 mM and 0.172 mM min

abruzzese [7]

Answer:

17.2 minutes is the value of the turnover number.

Explanation:

Using Michaelis-Menten equation:

$V = V_{max}\times \frac{[S]}{ (Km + [S])}$

$V_{max }=k_{cat}\times E_o$

Where :

$V_{max}$ = max rate velocity

[S] = substrate concentration

$K_m$ = Michaelis-Menten constant

V = reaction rate

$k_{cat}$ = catalytic rate constant

$E_o$ = initial enzyme concentration

We have :

$K_m=10.0mM$

$E_o=10.0\mu M=10.0\times 0.001 mM$

$V_{max}=0.172 mM/min$

$V_{max}$ is the rate is obtained when all enzyme is bonded to the substrate. $k_{cat}$ is termed as the turnover number.

$k_{cat}=\frac{V_{max}}{E_o}=\frac{0.172 mM}{10.0\times 0.001 mM}$

$=17.2 minutes$

17.2 minutes is the value of the turnover number.

3 0

3 years ago

4. If they..................me a question d have answered it.(ask/asked/had asked)

LekaFEV [45]

Answer:

had asked

Explanation:

If they had asked me a question, I would have answered it.

5 0

3 years ago

Read 2 more answers

How does Elnora feel about her future? A) She takes one day at a time. B) She is apprehensive and anxious. C) She is optimistic

Georgia [21]

Answer:

D) she is confident and has already made plans

4 0

3 years ago

Mr. Aguilar has ice on his wrist, literally. If the ice on Mr. Aguilar’s wrist (H2O) weighs 546 grams, how many ice particles ar

Lunna [17]

Answer:

The answer to your question is 1.83 x 10²⁵ particles

Explanation:

Data

particles of H₂O = ?

mass of H₂O = 546 g

Process

1.- Calculate the molar mass of Water

Molar mass = (2 x 1) + (1 x 16)

= 2 + 16

= 18 g

2.- Use proportions to find the number of particles. Use Avogadro's number.

18 g ---------------- 6.023 x 10²³ particles

546 g --------------- x

x = (546 x 6.023 x 10²³) / 18

3.- Simplification

x = 3.289 x 10²⁶ / 18

4.- Result

x = 1.83 x 10²⁵ particles

6 0

3 years ago

Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9

EleoNora [17]

Answer : The current passing between the electrodes is, $1.056\times 10^{-2}A$

Explanation :

First we have to calculate the charge of sodium ion.

$q=ne$

where,

q = charge of sodium ion

n = number of sodium ion = $2.68\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C$

Now we have to calculate the charge of chlorine ion.

$q'=ne$

where,

q' = charge of chlorine ion

n = number of chlorine ion = $3.92\times 10^{16}$

e = charge on electron = $1.6\times 10^{-19}C$

Now put all the given values in the above formula, we get:

$q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C$

Now we have to calculate the current passing between the electrodes.

$I=\frac{q}{t}+\frac{q'}{t}$

$I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}$

$I=1.056\times 10^{-2}A$

Thus, the current passing between the electrodes is, $1.056\times 10^{-2}A$

4 0

3 years ago

A certain mass of gàs occupied 5.0dm cube at 2 atm and 10°C .calculate d no of moles present​

A certain mass of gàs occupied 5.0dm cube at 2 atm and 10°C .calculate d no of moles present