Answer:
Part C: P2 = 0.30 atm
Part D: V1 = 16.22 L.
Explanation:
Part C:
Initial pressure (P1) = 2.67 atm
Initial volume (V1) = 5.54 mL
Final pressure (P2) =.?
Final volume (V2) = 49 mL
The final pressure (P2) can be obtained as follow:
P1V1 = P2V2
2.67 x 5.54 = P2 x 49
Divide both side by 49
P2 = (2.67 x 5.54)/49
P2 = 0.30 atm
Therefore, the final pressure (P2) is 0.30 atm
Part D:
Initial pressure (P1) = 348 Torr
Initial volume (V1) =?
Final pressure (P2) = 684 Torr
Final volume (V2) = 8.25 L
The initial volume (V1) can be obtained as follow:
P1V1 = P2V2
348 x V1 = 684 x 8.25
Divide both side by 348
V1 = (684 x 8.25)/348
V1 = 16.22 L
Therefore, the initial volume (V1) is 16.22 L
Events that happen over and over create/become a pattern
The question is incomplete, here is a complete question.
An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.
Answer : The new volume of the balloon is 25.7 L
Explanation :
Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.
![V\propto T](https://tex.z-dn.net/?f=V%5Cpropto%20T)
or,
![\frac{V_1}{T_1}=\frac{V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BT_1%7D%3D%5Cfrac%7BV_2%7D%7BT_2%7D)
where,
= initial volume of gas = 27.8 L
= final volume of gas = ?
= initial temperature of gas = ![13^oC=273+13=286K](https://tex.z-dn.net/?f=13%5EoC%3D273%2B13%3D286K)
= final temperature of gas = ![-9^oC=273+(-9)=264K](https://tex.z-dn.net/?f=-9%5EoC%3D273%2B%28-9%29%3D264K)
Now put all the given values in the above equation, we get:
![\frac{27.8L}{286K}=\frac{V_2}{264K}](https://tex.z-dn.net/?f=%5Cfrac%7B27.8L%7D%7B286K%7D%3D%5Cfrac%7BV_2%7D%7B264K%7D)
![V_2=25.7L](https://tex.z-dn.net/?f=V_2%3D25.7L)
Therefore, the new volume of the balloon is 25.7 L
The volume of a 6.67 m nacl solution
that contains 3.12 mol nacl is 0.468.
You just need to follow this formula:
C = n / V
So, it will be
V = n / C
<span> = 3.12 / 6.67 moles / Liter </span>
<span> = 0.468 L</span>
Answer: C. CO₂ and H₂O
Explanation:
Combustion reactions produce carbon dioxide and water.