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Vlad [161]
3 years ago
11

How are the digestive system and the urinary system similar?

Chemistry
1 answer:
Olenka [21]3 years ago
4 0

Answer:

While the digestive system collects and removes undigested solids, the excretory system filters compounds from the blood stream and collects them in urine. They are closely connected in controlling the amount of water in your body.

Explanation:

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The surface temperature of main-sequence stars increases as
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the surface temp of main sequence star increase as diameter increases

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The solubility of copper(i) chloride is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl (cucl=99.00 g mol-1).
garri49 [273]
Convert  Mg  to  grams
1g =1000mg  what  about  3.91  Mg
=  3.91mg  x  1g/1000mg=  3.91  x10^-3 g
moles= mass/molar mass
that  is  3.91  x10^-3g  /99 g/mol=3.95 x10^-5moles
concentration=   moles  /  vol   in  liters

that  is  3.95  x10^-5/100  x1000=  3.94  x10^-4M

equation for  dissociation  of  CUCl=   CUCl---->  CU^+   +Cl^-

Ksp=(CU+)(CI-)
that  is  (3.95  x10^-4)(3.95  x10^-4)
Ksp=  1.56  x10^-7
3 0
3 years ago
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r-ruslan [8.4K]

Answer:

no

Explanation:

Because I have lost and I dont know where is the worksheet

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A 25. 0-ml sample of 0. 150 m hydrocyanic acid is titrated with a 0. 150 m naoh solution. What is the ph beforeany base is added
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explain why it is a common laboratory procedure to heat analytical reagents and store them in a dessicated atmosphere (a sealed
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Explanation:

Most reagent forms are going to absorb water from the air; they're called "hygroscopic".  Water presence can have a drastic impact on the experiment being performed  For fact, it increases the reagent's molecular weight, meaning that anything involving a very specific molarity (the amount of molecules in the final solution) will not function properly.

Heating will help to eliminate water, although some chemicals don't react well to heat, so it shouldn't be used for all.  A dessicated environment is simply a means to  "dry."  That allows the reagent with little water in the air to attach with.

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