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3 years ago

What is the name of the process the puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP?

1 answer:

6 0

I think the correct answer is hydrolysis. The name <span>of the process that puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP is called hydrolysis. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>

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Which of the following events happens first in the development of a new organism? A. A sperm fertilizes an egg to form a zygote.

Juli2301 [7.4K]

The development of a new organism begins with answer A, the sperm must fertlize an egg to form the zygote.

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3 years ago

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What is calculated by speed of light/wavelength?

zhenek [66]

Frequency of oscillation = speed of light/wave length

6 0

3 years ago

A boat is traveling with a velocity of 18 meters/second relative to water and the river is flowing at a velocity of 2.5 meters/s

ddd [48]

Vt = Vboat - Vriver
Vt = 18 - 2.5 = 15.5 m/s

If the boat's direction is the same as the water, you sum the velocities of the river and the boat .

8 0

3 years ago

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A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated

Lelu [443]

Incomplete question as we have not told to find what quantity.The complete question is here

A spherical capacitor contains a charge of 3.50 nC when connected to a potential difference of 210.0 V. Its plates are separated by vacuum and the inner radius of the outer shell is 5.00 cm.calculate: (a) the capacitance; (b) the radius of the inner sphere; (c) the electric field just outside the surface of the inner sphere.

Answer:

(a) $C=16.7pF$

(b) $r_{a} =3.749cm$

Explanation:

Given data

$Q=3.50nC\\V=210V\\r_{b}=5.0cm$

For part (a)

The Capacitance given by:

$C=\frac{Q}{V}\\ C=\frac{3.50*10^{-9} C}{210V}\\C=1.6666*10^{-11}F\\or\\C=16.7pF$

For part (b)

The Capacitance of coordinates is given as

$C=\frac{4\pi e}{\frac{1}{r_{a} }-\frac{1}{r_{b} } }\\ So\\{\frac{1}{r_{a} }-\frac{1}{r_{b} } }=\frac{4\pi *8.85*10^{-12} }{1.666*10^{-11}}=6.672m^{-1} \\ \frac{1}{r_{a} }=6.672+(1 /0.05)\\\frac{1}{r_{a} }=26.672\\r_{a} =1/26.672\\r_{a} =0.0375m\\r_{a} =3.749cm$

For part (c)

The electric field according to Gauss Law is given by:

$EA=\frac{Q}{e}\\ E=\frac{Q}{4\pi er_{a}^{2} }=\frac{kQ}{r_{a}^{2}}\\ E=\frac{9*10^{9}*3.50*10^{-9} }{(0.0375m)^{2} }\\ E=2.24*10^{4} N/C$

7 0

3 years ago

Write the equation of a function h(t) that represents the amount of heat in joules required to heat the bar to a temperature of

bearhunter [10]

The initial temperature of the bar is 25. To get to the t temperature you need to add (t-25) degrees Celsius.

for 1 degree................... 7 Joules
y given degree........ p Joules

p=7y

In our case y=(t-25) .

h(t) = 7(t-25) which is the final answer.

8 0

3 years ago