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tensa zangetsu [6.8K]
3 years ago
7

What is the name of the process the puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP?

Physics
1 answer:
hoa [83]3 years ago
6 0
I think the correct answer is hydrolysis. The name <span>of the process that puts adenosine diphosphate (ADP) and phosphate (P) together to reform ATP is called hydrolysis. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
You might be interested in
Winds are deflected to the (right/left) ___ as they move into a low pressure area in the Northern Hemisphere.
SashulF [63]

Winds are deflected to the right as they move into a low pressure area in the Northern Hemisphere.

<u>Explanation:</u>

Winds decide the motion of ocean currents which forms the surface waves in the Earth's atmosphere to maintain the pressure region. The motion of ocean currents is based on Coriolis force which states the direction of motion of an object in a rotating system.

In the case of Earth, the Coriolis force has an effect on the ocean currents which are deflected from maximum to minimum pressure region in a curved path. So the winds formed by the ocean currents will generally get deflected at the right as they move into a low pressure area at the Northern Hemisphere from the high pressure region.

8 0
3 years ago
What is the energy of a 9 kg brick that is
Tems11 [23]

Explanation:

formula for energy is k. e = ½mv²

m= 9

v= 75

k. e = ½×9×75 =337•5

6 0
2 years ago
1500 kg wrecking ball traveling at a speed of 3.5 m/s hits a wall that does not crumble but is pushed back 75 cm. If the wreckin
Rudiy27

Answer:

The size of the force that pushes the wall is 12,250 N.

Explanation:

Given;

mass of the wrecking ball, m = 1500 kg

speed of the wrecking ball, v = 3.5 m/s

distance the ball moved the wall, d = 75 cm = 0.75 m

Apply the principle of work-energy theorem;

Kinetic energy of the wrecking ball = work done by the ball on the wall

¹/₂mv² = F x d

where;

F is the size of the force that pushes the wall

¹/₂mv² = F x d

¹/₂ x 1500 x 3.5² = F x 0.75

9187.5 = 0.75F

F = 9187.5 / 0.75

F = 12,250 N

Therefore, the size of the force that pushes the wall is 12,250 N.

7 0
3 years ago
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.4 kg gibbon
Katarina [22]

Answer:

upward force acting = 261.6 N

Explanation:

given,

mass of gibbon = 9.4 kg

arm length = 0.6 m

speed of the swing

net force must provide

F_{branch} + F_{gravity}=F_{centripetal}

force of gravity = - mg

F_{branch}=F_{centripetal}-F_{gravity}

                        = \dfrac{mv^2}{r} + mg

                        = m(\dfrac{3.4^2}{0.6} +9.8)

                        =9 x 29.067

                        = 261.6 N

upward force acting = 261.6 N

7 0
3 years ago
a student measure the mass of an 8 cm^3 block of brown sugar to be 12.9 g. what is the density of the brown sugar?
schepotkina [342]
Density = mass / volume ;
1 Cubic Centimeter = 0,000001 Cubic Meter
8 cm^3 = 0.000008 m^3
12,9 g = 0,0129 kg


The density is 0,0129 kg/ 0,000008 m^3 = <span><u>1612,5 kg/m^3</u> </span>
4 0
3 years ago
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