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3 years ago

What are non-contact forces please include example in your answer

Physics

2 answers:

Alina [70]3 years ago

4 0

Answer:

Gravitational force. Magnetic force. Electrostatics. Nuclear force.

Explanation:

Apple falling from a tree

raindrops falling from the sky

Katen [24]3 years ago

4 0

The most familiar non-contact force is gravity, which confers weight. In contrast a contact force is a force applied to a body by another body that is in contact with it. All four known fundamental interactions are non-contact forces: Gravity, the force of attraction that exists among all bodies that have mass.

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What is Quantum Physics?

vredina [299]

Study of interaction between matter and energy using mechianical description

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4 years ago

A car is idling at a stoplight. When the light turns green, the car takes 12 seconds to accelerate to 18.7 m/s. What is the aver

Sonbull [250]

Answer:

1.6 m/s^2

Explanation:

3 0

4 years ago

An object is formed by attaching a uniform, thin rod with a mass of mr = 6.85 kg and length L = 5.76 m to a uniform sphere with

Ket [755]

Answer:

Part a)

$I = 1879.7 kg m^2$

Part b)

$\alpha = 0.70 rad/s^2$

Part c)

$I = 153.8 kg m^2$

Part 4)

angular acceleration will be ZERO

Part 5)

$I = 345.6 kg m^2$

Explanation:

Part a)

Moment of inertia of the system about left end of the rod is given as

$I = \frac{m_r L^2}{3} + (\frac{2}{5} m_s R^2 + m_s(R + L)^2)$

So we have

$I = \frac{m_r(4R)^2}{3} + (\frac{2}{5}(5m_r) R^2 + (5m_r)(R + 4R)^2)$

$I = \frac{16}{3}m_r R^2 + (2m_r R^2 + 125 m_rR^2)$

$I = (\frac{16}{3} + 127)m_r R^2$

$I = (\frac{16}{3} + 127)(6.85)(1.44)^2$

$I = 1879.7 kg m^2$

Part b)

If force is applied to the mid point of the rod

so the torque on the rod is given as

$\tau = F\frac{L}{2}$

$\tau = 460(2R)$

$\tau = 460 \times 2 \times 1.44$

$\tau = 1324.8 Nm$

now angular acceleration is given as

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{1324.8}{1879.7}$

$\alpha = 0.70 rad/s^2$

Part c)

position of center of mass of rod and sphere is given from the center of the sphere as

$x = \frac{m_r}{m_r + m_s}(\frac{L}{2} + R)$

$x = \frac{m_r}{6 m_r}(3R) = \frac{R}{2}$

so moment of inertia about this position is given as

$I = \frac{m_r L^2}{12} + m_r(\frac{L}{2} + \frac{R}{2})^2 + (\frac{2}{5} m_s R^2 + m_s(\frac{R}{2})^2)$

so we have

$I = \frac{m_r (16R^2)}{12} + m_r(\frac{5R}{2})^2 + \frac{2}{5}(5m_r)R^2 + (5m_r)(\frac{R^2}{4})$

$I = m_r R^2(\frac{16}{12} + \frac{25}{4} + 2 + \frac{5}{4})$

$I = 6.85(1.44)^2\times 10.83$

$I = 153.8 kg m^2$

Part 4)

If force is applied parallel to the length of rod

then we have

$\tau = \vec r \times \vec F$

$\tau = 0$

so angular acceleration will be ZERO

Part 5)

moment of inertia about right edge of the sphere is given as

$I = \frac{m_r L^2}{12} + m_r(\frac{L}{2} + 2R)^2 + (\frac{2}{5} m_s R^2 + m_s(R)^2)$

so we have

$I = \frac{m_r (16R^2)}{12} + m_r(4R)^2 + \frac{2}{5}(5m_r)R^2 + (5m_r)(R^2)$

$I = m_r R^2(\frac{16}{12} + 16 + 2 + 5)$

$I = 6.85(1.44)^2\times 24.33$

$I = 345.6 kg m^2$

6 0

3 years ago

Are predators or their prey more likely to be successful?

mihalych1998 [28]

Predator because they are the one’s preying on the animals, the chances of the prey getting away is slim.

3 0

3 years ago

Read 2 more answers

Which characteristics do temperate marine and temperate continental climates have in common? Check all that apply.

katrin2010 [14]

Answer:

moderate amount of precipitation

two seasons with temperature differences

Explanation:

Temperate marine climates is also known as oceanic climate and areas who experience this climate are closer to oceans. There is relative precipitation all round the year due to the close proximity to the water body and have the hot and cold season.

The temperate continental climate also has two season and relative rainfall but found in the areas along the Northern hemispheres.

Both climates have moderate amount of precipitation and two seasons with temperature differences.

6 0

3 years ago