Answer:
Answer:
71.6°
Explanation:
According to the diagram
ED = 6 feet
DA = EB = 3 feet
AC = 15 feet
AB = ED = 6 feet
BC = AC - AB = 15 - 6 = 9 feet
Let the angle is θ from the horizontal
By the triangle EBC
tanθ = BC / EB = 9 / 3
tanθ = 3
θ = 71.6°
Thus, the angle from the horizontal is 71.6°.
Explanation:
It's the angle made by the incident ray when it's perpendicular to the surface. (Perpendicular lines are the lines that form a graph or like a 90-degree angle)
Answer:
The man's velocity relative to the moving walkway is, v₂₃ = 0.2 m/s
Explanation:
Given data,
The speed of the moving walkway, v₁₂ = 0.9 m/s
The speed of the man walking on a walkway to the stationary observer, v₁₃ = 1.1 m/s
The speed of the man walking on a walkway to the walkway, v₂₃ = ?
The formula for relative velocity is,
<em> v₁₃ = v₁₂ + v₂₃</em>
∴ v₂₃ = v₁₃ - v₁₂
Substituting the values,
v₂₃ = 1.1 - 0.9
= 0.2 m/s
Hence, the man's velocity relative to the moving walkway is, v₂₃ = 0.2 m/s