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3 years ago

What are non-contact forces please include example in your answer

Physics

2 answers:

Alina [70]3 years ago

4 0

Answer:

Gravitational force. Magnetic force. Electrostatics. Nuclear force.

Explanation:

Apple falling from a tree

raindrops falling from the sky

Katen [24]3 years ago

4 0

The most familiar non-contact force is gravity, which confers weight. In contrast a contact force is a force applied to a body by another body that is in contact with it. All four known fundamental interactions are non-contact forces: Gravity, the force of attraction that exists among all bodies that have mass.

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Which equation was used by Albert Einstein to explain the photoelectric effect? [E = energy, h = Planck’s constant, and v = freq

Afina-wow [57]

Answer:

E = hv

Explanation:

The photoelectric effect is a phenomenon when the electromagnetic waves of a particular wavelength strike on the metal plate like zinc, it ejects the free electrons.
The ejected electrons have the kinetic energy and this energy is responsible for the electric energy.
The kinetic energy of the emitted electrons is linked with the frequency of the incident rays.
If the rays hitting the metal plate is below the minimum required threshold value, the photoelectrons are not ejected.
The photoelectric equation is given by

E = hν - ∅

Where, ∅ is the minimum energy required to remove an electron.

6 0

3 years ago

Which simple machine is a doorknob?

Anestetic [448]

The answer is wheel and axle

3 0

3 years ago

Las condiciones iniciales de un gas son 3000 cm3

slava [35]

Answer:

T'=92.70°C

Explanation:

To find the temperature of the gas you use the equation for ideal gases:

$PV=nRT$

V: volume = 3000cm^3 = 3L

P: pressure = 1250mmHg; 1 mmHg = 0.001315 atm

n: number of moles

R: ideal gas constant = 0.082 atm.L/mol.K

T: temperature = 27°C = 300.15K

For the given values you firs calculate the number n of moles:

$n=\frac{PV}{RT}=\frac{(1520[0.001315atm])(3L)}{(0.082\frac{atm.L}{mol.K})(300.15K)}=0.200moles$

this values of moles must conserve when the other parameter change. Hence, you have V'=2L and P'=3atm. The new temperature is given by:

$T'=\frac{P'V'}{nR}=\frac{(3atm)(2L)}{(0.200\ moles)(0.082\frac{atm.L}{mol.K})}=365.85K=92.70\°C$

hence, T'=92.70°C

8 0

3 years ago

The acceleration due to gravity is g at the earth's surface. an earth satellite is orbiting at a distance from the earth's surfa

disa [49]

The acceleration due to gravity is g/4

The acceleration above the earth surface is given by the relation

g^'=gr^2/〖(h+r)〗^2

Since the satellite orbits the earth in a orbit of radius equal to earth radius, therefore

g^'=(gr^2)/〖(r+r)〗^2 =g/4

Thus the acceleration due to gravity on the satellite is g/4.

6 0

3 years ago

Two objects are dropped from rest from the same height. Object A falls through a distance Da and during a time t, and object B f

stiv31 [10]

Answer:

Da=(1/4)Db

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

When s = Da, t = t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times t^2\\\Rightarrow Da=\frac{1}{2}at^2$

When s = Db, t = 2t

$s=ut+\frac{1}{2}at^2\\\Rightarrow Da=0\times t+\frac{1}{2}\times a\times (2t)^2\\\Rightarrow Db=\frac{1}{2}a4t^2$

Dividing the two equations

$\frac{Da}{Db}=\frac{\frac{1}{2}at^2}{\frac{1}{2}a4t^2}=\frac{1}{4}\\\Rightarrow \frac{Da}{Db}=\frac{1}{4}\\\Rightarrow Da=\frac{1}{4}Db$

Hence, Da=(1/4)Db

3 0

3 years ago